A batter hits two baseballs with the same force. One hits the ground near third base. The other is a home run out of the park. W
2 answers:
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Answer:
The necessary separation between the two parallel plates is 0.104 mm
Explanation:
Given;
length of each side of the square plate, L = 6.5 cm = 0.065 m
charge on each plate, Q = 12.5 nC
potential difference across the plates, V = 34.8 V
Potential difference across parallel plates is given as;
Where;
d is the separation or distance between the two parallel plates;
Therefore, the necessary separation between the two parallel plates is 0.104 mm
Answer:
His resulting velocity will be 0.187 m/s backwards.
Explanation:
Given:
Mass of the man is,
Mass of the ball is,
Initial velocity of the man is,
Initial velocity of the ball is,
Final velocity of the ball is,
Final velocity of the man is,
In order to solve this problem, we apply law of conservation of momentum.
It states that sum of initial momentum is equal to the sum of final momentum.
Momentum is the product of mass and velocity.
Initial momentum = Initial momentum of man and ball
Initial momentum =
Final momentum = Final momentum of man and ball
Final momentum =
Now, initial momentum = final momentum
The negative sign implies backward motion of the man.
Therefore, his resulting velocity is 0.187 m/s backwards.