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pishuonlain [190]
3 years ago
13

A batter hits two baseballs with the same force. One hits the ground near third base. The other is a home run out of the park. W

here was there more work done?
Physics
2 answers:
stealth61 [152]3 years ago
7 0
At the end of the baseball bat, because with the length of the bat he had a longer reach and the end of the bat was moving faster than his hands were

Keith_Richards [23]3 years ago
7 0

Answer:

the one that went out of the park.

Explanation:

work is the total power and distance. so if it went farther, its more, because it takes more distance to make it back to the original spot.

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In the lesson a thermos is presented as an example of an isolated energy system. How could you change the thermos into an open e
iVinArrow [24]
If you want to change the thermos into an open energy system, you have to remove the lid. Once the lid is removed, the energy is no longer contained inside the thermos bottle. From the bottle, the energy dissipates to the environment.
7 0
4 years ago
Read 2 more answers
The drawing shows two long, thin wires that carry currents in the positive z direction. Both wires are parallel to the z axis. T
erica [24]

Answer:

The magnitude of the magnetic field at the origin is 2.56\times 10^{-6}\ T.

Explanation:

Given :

50-A wire is in the x-z plane and is 5 m from the z axis.

Also , 40-A wire is in the y-z plane and is 4 m from the z axis.

Now , since both the wire are perpendicular to each other .

Therefore , magnetic field are also perpendicular to each other .

Magnetic field at origin due to wire 1 is :

B_1=\dfrac{\mu_oI_1}{2\pi R_1}\\\\B_1=\dfrac{(50)\mu_o}{2\pi( 5)}\\\\B_1=\dfrac{5\mu_o}{\pi}

Magnetic field at origin due to wire 2 is :

B_2=\dfrac{\mu_oI_2}{2\pi R_2}\\\\B_2=\dfrac{(40)\mu_o}{2\pi( 4)}\\\\B_2=\dfrac{4\mu_o}{\pi}

Now , therefore net magnetic field is :

B=\sqrt{B_1^2+B_2^2}\\\\B=\sqrt{(\dfrac{5\mu_o}{\pi})^2+(\dfrac{4\mu_o}{\pi})^2}\\\\B=\dfrac{\sqrt{41}\mu_o}{\pi}

Putting value of \mu_o=4\pi \times 10^{-7}\ H/m

We get ,

B=\sqrt{41}\times 4\times 10^{-7}\\B=2.56\times 10^{-6}\ T

Therefore, the magnitude of the magnetic field at the origin is 2.56\times 10^{-6}\ T.

5 0
3 years ago
Question is in the picture
Svetradugi [14.3K]

the more pressure put on the string, the more frequency and higher pitch.

4 0
4 years ago
Which statement is true about acceleration?
dmitriy555 [2]
C is the correct answer.
6 0
4 years ago
Read 2 more answers
One mole of a gas is placed in a closed system with a 20 L vessel initially at T = 300 K. The vessel is then isothermally expand
Elden [556K]

Answer:

Given that

P = RT/V + a/V²

We know that

H= U + PV

For T= Constant  (ΔU=0)

ΔH= ΔU +Δ( PV)

ΔH= Δ( PV)

P = RT/V + a/V²

P V= RT + a/V

dH/dV = d(RT + a/V)/dV

dH/dV = - a/V²

So the expression of dH/dV

\dfrac{dH}{dV}=\dfrac{-a}{V^2}

b)

In isothermal process

\Delta H=nRT\ln{\dfrac{V_2}{V_1}}      (ΔU=0)

Now by putting the all values

\Delta H=nRT\ln{\dfrac{V_2}{V_1}}

\Delta H=1\times 0.08206\times 300\ln{\dfrac{40}{20}}

ΔH = 17.06 L.atm

8 0
3 years ago
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