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pishuonlain [190]
2 years ago
13

A batter hits two baseballs with the same force. One hits the ground near third base. The other is a home run out of the park. W

here was there more work done?
Physics
2 answers:
stealth61 [152]2 years ago
7 0
At the end of the baseball bat, because with the length of the bat he had a longer reach and the end of the bat was moving faster than his hands were

Keith_Richards [23]2 years ago
7 0

Answer:

the one that went out of the park.

Explanation:

work is the total power and distance. so if it went farther, its more, because it takes more distance to make it back to the original spot.

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mylen [45]

The experiments will involve two billiard balls of known masses, m₁ and m₂, and velocities u₁ and u₂. The two are allowed to collide and the velocities of the balls after the collision v₁ and v₂ are recorded.

The momentum before and after the collision is then calculated as follows:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

<h3>What is the statement of the law of conservation of momentum?</h3>

The law of the conservation of momentum states that the momentum before and after collision in a system of colliding bodies is conserved

The momentum of a body is calculated using the formula below:

Momentum = mass * velocity.

Hence, for the two billiard balls, the momentum before and after the collision is conserved.

Learn more about momentum at: brainly.com/question/1042017

#SPJ1

3 0
1 year ago
How well a student reads can most likely be effected by
Burka [1]
Their cognitive skills and their ability to learn
3 0
2 years ago
Why are there two fluoride ions in magnesium fluoride but only one fluoride ion in lithium fluoride
postnew [5]
This would be more of a chemistry question. Remember magnesium has a charge of 2+, and would need to hand off its two extra electrons. Fluorine can only take one electron at a time, so there needs to be two fluorines to take one magnesium's 2 electrons. 

With lithium, it has a +1 charge, so it has one extra electron, which it can hand off to just 1 fluorine atom. 

Another way of looking at this is: Mg^{2+} + 2F^{-} = MgF2  (the charges must balance out to zero)

Li^{+} + F^{-} = LiF (the charges balance out to zero)
5 0
3 years ago
Read 2 more answers
When does the fall equinox occur in the northern hemisphere
aivan3 [116]

Here is your answer

On 23rd September

HOPE IT IS USEFUL

7 0
2 years ago
Even when the head is held erect, as in the figure below, its center of mass is not directly over the principal point of support
alexandr1967 [171]

We are asked to determine the force required by the neck muscle in order to keep the head in equilibrium. To do that we will add the torques produced by the muscle force and the weight of the head. We will use torque in the clockwise direction to be negative, therefore, we have:

\Sigma T=r_{M\perp}(F_M)-r_{W\perp}(W)

Since we want to determine the forces when the system is at equilibrium this means that the total sum of torque is zero:

r_{M\perp}(F_M)-r_{W\perp}(W)=0

Now, we solve for the force of the muscle. First, we add the torque of the weight to both sides:

r_{M\perp}(F_M)=r_{W\perp}(W)

Now, we divide by the distance of the muscle:

(F_M)=\frac{r_{W\perp}(W)}{r_{M\perp}}

Now, we substitute the values:

F_M=\frac{(2.4cm)(50N)}{5.1cm}

Now, we solve the operations:

F_M=23.53N

Therefore, the force exerted by the muscles is 23.53 Newtons.

Part B. To determine the force on the pivot we will add the forces we add the vertical forces:

\Sigma F_v=F_j-F_M-W

Since there is no vertical movement the sum of vertical forces is zero:

F_j-F_M-W=0

Now, we add the force of the muscle and the weight to both sides to solve for the force on the pivot:

F_j=F_M+W

Now, we plug in the values:

F_j=23.53N+50N

Solving the operations:

F_j=73.53N

Therefore, the force is 73.53 Newtons.

8 0
9 months ago
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