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andreev551 [17]
4 years ago
15

The engine of a 1520-kg automobile has a power rating of 75 kW. Determine the time required to accelerate this car from rest to

a speed of 100 km/h at full power on a level road. Is your answer realistic?
Physics
1 answer:
LUCKY_DIMON [66]4 years ago
3 0

Answer:

t=15.68 s

Explanation:

Given that

m = 1520 kg

P =75 KW

We know that

Power  ,P = F .v

F=force

v=velocity

v= 100 km/h

v=\dfrac{1000}{3600}\times 100\ m/s

v=27.77 m/s

75 x 1000  = F x 27.77

F= \dfrac{75000}{27.77}\ N

F= 2700.75 N

F= m a

m=mass

a=acceleration

2700.75 = 1520 x a

 a=1.77 m/s²

time t given as

v= u + a t

27.77 = 0 + 1.77 x t

t=15.68 s

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riadik2000 [5.3K]

Based on the ideal gas equation, the pressure (P), volume (V) and temperature (T) corresponding to n moles of an ideal gas are related as:

PV = nRT

where R = gas constant

Under conditions of constant pressure and  number of moles:

The volume is directly proportional to the pressure. Therefore, as the temperature drops the volume will also decrease.

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This is also known as the Charles Law.

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3 years ago
Which statements describe the energy in a food web? Check all that apply. When an organism eats another organism, it loses energ
Neko [114]

Answer:  Producers have the greatest amount of available energy.

When an organism eats another organism, it gains energy.

Explanation:

A food chain is a linear sequence of transfer of food and energy when one organism is eaten by the other organism. A food web is the interconnection of two or more food chains. This happens when one organism belong to one food chain also consume organisms of same food chain or other food chain. A food chain includes trophic levels on the basis of the mode of feeding of the living beings.

Among the options given, Producers have the greatest amount of available energy. and

When an organism eats another organism, it gains energy. are correct.

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When one organism eats other organism it gains energy because of the assimilation and digestion of the organism as food.

8 0
3 years ago
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The system below uses massless pulleys and ropes. The coefficient of friction is μ. Assume that M1 and M2 are sliding. Gravity i
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Explanation:

Using Newtons second law on each block

F = m*a

Block 1

T_{1} - u*g*M_{1} = M_{1} *a \\\\T_{1} = M_{1}*(a + u*g) ... Eq1

Block 2

T_{2} - u*g*M_{2} = M_{2} *a \\\\T_{2} = M_{2}*(a + u*g) ... Eq2

Block 3

- (T_{1} + T_{2} ) + g*M_{3} = M_{3} *a \\\\T_{1} + T_{2} = M_{3}*( -a + g) ... Eq3

Solving Eq1,2,3 simultaneously

Divide 1 and 2

\frac{T_{1} }{T_{2}} = \frac{M_{1}*(a+u*g)}{M_{2}*(a+u*g)}  \\\\\frac{T_{1} }{T_{2}} = \frac{M_{1} }{M_{2} }\\\\ T_{1} =  \frac{M_{1} *T_{2} }{M_{2} } .... Eq4

Put Eq 4 into Eq3

T_{2} = \frac{M_{3}*(g-a) }{1+\frac{M_{1} }{M_{2} } }  ...Eq5

Put Eq 5 into Eq2 and solve for a

a = \frac{M_{3}*g -u*g*(M_{1} + M_{2}) }{M_{1} + M_{2} + M_{3} }  .... Eq6

Substitute back in Eq2 and use Eq4 and solve for T2 & T1

T_{2} = M_{2}*M_{3}*g*(\frac{1-u}{M_{1} + M_{2}+M_{3}})\\\\T_{1} = M_{1}*M_{3}*g*(\frac{1-u}{M_{1} + M_{2}+M_{3}})\\\\

5 0
4 years ago
Organ pipe a, with both ends open, has a fundamental frequency of 340 hz. the third harmonic of organ pipe b, with one end open,
Sphinxa [80]
The fundamental frequency of the open pipe A
Length 'L₀' is, f₀ = U/2L₀ = 340 H₂
the speed of sound in air V=  343m/s
∴343/2L₀ = 340 → length L₀ = 343/2 ×340 = 0.5044 = 50.44
The third harmonic of closed pipe 'B' is 
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Explanation :

It is given that, a heavy box is in the back of a truck and the truck is accelerating to the right.

The description is shown in<em> figure 1</em>. Here, the forces that act on both box and the truck are the normal force, the frictional force and their weight mg.

The free body diagram is shown in <em>figure 2</em>. This shows the total forces            ( F = ma )acting on the truck. As a result, the truck will move in a forward direction.

Hence, this is the required explanation.

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3 years ago
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