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2 years ago

What is the range of the function?

Mathematics

1 answer:

Goryan [66]2 years ago

3 0

Answer:

1. all real numbers less than or equal to 4 = </= 4.

Answer = YES!

2. all real numbers less than or equal to -3 = </= -3.

Answer = YES!

3. all real numbers greater than or equal to 4 = >/= 4

Answer = YES!

4. all real numbers greater than or equal to -3 = >/= -3

Answer = NO!

Step-by-step explanation:

1. all real numbers less than or equal to 4 = </= 4.

1 + 1 = 2

1 + 2 = 3

2 + 2 = 4

2. all real numbers less than or equal to -3 = </= -3.

1 - 1 = 0

1 - 2 = -1

1 - 3 = -2

1 - 4 = -3

3. all real numbers greater than or equal to 4

1 + 1 = 2

1 + 2 = 3

1 + 3 = 4

1 + 4 = 5

4. all real numbers greater than or equal to -3

1 - 1 = 0

1 - 2 = -1

1 - 3 = -2

1 - 4 = -3

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We have to solve for m:

$\begin{gathered} -26-4m=-2(2m+13) \\ -2(13+2m)=-2(2m+13) \\ -2=-2 \end{gathered}$

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1 year ago

Halp ;-; A florist is using 36 flowers to make 4 identical arrangements. How many flowers will be in each arrangement?

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2 years ago

The product of 6 and 1 3/4<br> is it less than 6 equal to 6 or greater than 6

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3 years ago

Read 2 more answers

An arrow is shot vertically upward from a platform 45 feet high at a rate of 168 ft/sec. Use the quadratic function

Maksim231197 [3]

Answer:

5.3 s

Step-by-step explanation:

a) since the height is defined by a function, we can find the turning point of the quadratic , which is where the ball will have the highest point. The turning point is where the gradient is equal to zero so we differentiate first

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2 years ago

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Julia is going to the store to buy candies. Small candies cost $4 and extra-large candies cost $12.She needs to purchase at leas

BartSMP [9]

Answer:

Small candies $=9$

Extra large candies $=12$

Step-by-step explanation:

Let small candies $=x$

Extra large candies $=y$

the number of candies is at least $20$ .

$x+y\geq20$

Cost of $1$ small candy $=\$4$

Cost of $1$ extra large candy $=\$12$

but she has only $\$180$ to spend

$4x+12y\leq180$

Solve for

$x+y=20.......(1)\\4x+12y=180.....(2)\\eqn(2)-eqn(1)\times4\\8y=100\\y=\frac{100}{8} \\y=\frac{25}{8} \\from\ eqn(1)\\x+\frac{25}{2}=20\\ x=20-\frac{25}{2} \\x=\frac{15}{2}$

Since number of candies should be integer.

let $x=7,y=13$

total spend $4\times7+12\times13=184$ which is more than $\$180$ , so this combination is not possible.

$let\ x=8,y=12\\8\times4+12\times12=176$

She has $\$4$ more so she can buy $1$ more small candy.

Hence small candy $=9$

extra large candy $=12$

4 0

2 years ago