<u>We are given:</u>
Mass of the rocket = 10 kg
Weight of the Rocket = 100 N
Upward thrust applied by the rocket = 400 N
<u>Net upward force on the rocket:</u>
We are given that gravity pulls the rocket with a force of 100 N
Also, the rocket applied a force of 400N against gravity
Net upward force = Upward thrust - Force applied by gravity
Net upward force = 400 - 100
Net upward force = 300 N
<u>Upward Acceleration of the Rocket:</u>
From newton's second law:
F = ma
<em>replacing the variables</em>
300 = 10 * a
a = 30 m/s²
Answer:B
Explanation:
Option A:
In the nuclear reactions,neutron can be split into proton an electron.
In this case,the number of protons are increasing,increasing the atomic number.
Hence,the atomic number is not conserved.
Option B:
In any reaction the sum of number of neutrons and number of protons remain constant before and after the reaction.
Option C:
The mass number may change for the atoms.For example emission reduces the atomic number by
Option D:
In the nuclear reactions,neutron can be split into proton an electron.
So,they number of neutrons may change.
Answer:
90 meters
Explanation:
To find the distance in which Bob catches up with Wendy, you first write down the motion equations of both Bob and Wendy.
Wendy has a constant speed, then you have:
(1)
Bob has an accelerated motion, then, his equation of motion is:
(2)
v1: constant speed of Wendy = 3.00 m/s
v2: initial speed of Bob = 0 m/s
a: acceleration of Bob = 0.200m/s^2
When Bob catches up with Wendy x1 = x2, then you equal both equations and solve for time t:
you replace the values of a and v1:
Finally, you replace this value of time either the equation for x1 or the equation for x2, and you calculate the distance:
hence, Bob catches up with Wendy for a distance of 90m
Answer:
(a) 0.115 m
(b) 2.08 x 10^-5 J
Explanation:
mass of bob, m = 81 g = 0.081 kg
The equation of oscillation is given by
θ = 0.068 Cos {9.2 t + Ф}
Now by comparison
The angular velocity
ω = 9.2 rad/s
(a)
where, L be the length of the pendulum
L = 0.115 m
(b) A = L Sinθ
A = 0.115 x Sin 0.068
A = 7.8 x 10^-3 m
Maximum kinetic energy
K = 0.5 x mω²A²
K = 0.5 x 0.081 x 9.2 x 9.2 x 7.8 x 7.8 x 10^-6
K = 2.08 x 10^-5 J
Answer:
His third law states that for every action (force) in nature there is an equal and opposite reaction. In re-action, a thrusting force is produced on the engine mount. The thrust accelerates the rocket as described by Newton's second law of motion.
Explanation: