Answer:
answer A
Step-by-step explanation:
To get the answer to this equation you first cancel out the 6! ;)
(x^2-1)(6x-1) / (x+1)
Then rewrite x^2-1 in the form a^2 + b^2, where a=x and b=1
(x^2-1^2)(6x-1) / (x+1)
Then use the difference of squares!
(x+1)(x-1)(6x-1) / (x+1)
LASTLY cancel "x+1" !
so ur answer is (x-1) (6x-1)
That makes the correct answer to this problem answer choice (D) (x-1) (6x-1)
YW!!! ;)
The domain of (f/g)(x) considers the domains of g(x) and f(x) and makes sure that g(x)≠0
because (f/g)(x)=f(x)/g(x)
and division by 0 is not allowed
the domains of f(x) and g(x) are all real numbers
now find what make g(x)=0
0=x-9
9=x
9 is restricted from the domain
domain is all real numbers except 9
so


the domain is all real numbers except for 9