The bigger the starting force, the further the distance moved by the car?
Answer:
Maximum speed of the car is 26.56 m/s.
Explanation:
Given that,
Mass of the car, m = 1200 kg
Radius of the curve, r = 90 m
The coefficient of friction between tires and the road is 0.8.
We need to find the maximum speed of the car. On the circular curve, the centripetal force is balanced by the force of friction. So,

So, the maximum speed of the car is 26.56 m/s.
Answer:
31.905 ft/s²
Explanation:
Given that
Mass of the pilot, m = 120 lb
Weight of the pilot, w = 119 lbf
Acceleration due to gravity, g = 32.05 ft/s²
Local acceleration of gravity of found by using the relation
Weight in lbf = Mass in lb * (local acceleration/32.174 lbft/s²)
119 = 120 * a/32. 174
119 * 32.174 = 120a
a = 3828.706 / 120
a = 31.905 ft/s²
Therefore, the local acceleration due to gravity at that elevation is 31.905 ft/s²
Answer:
35.792 N
Explanation:
d = Diameter of rod = 2.7 cm
h = Length of rod = 81.7 cm
= Density of rod = 7800 kg/m³
g = Acceleration due to gravity = 9.81 m/s²
Volume of rod

Mass is given by

Weight is given by

The weight of the rod is 35.792 N