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4 years ago

Question 1

Physics

1 answer:

creativ13 [48]4 years ago

6 0

Answer:

Epsilon Eridani

Explanation:

This is in the main sequence as you can see there is an area called "main sequence all you have to do is read all the stars and to see which one is in there and that is The epsilon eridani

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Help! Plssssss 30 points!

Rashid [163]

The bigger the starting force, the further the distance moved by the car?

7 0

3 years ago

What is the maximum speed with which a 1200-kg car can round a turn of radius 90.0 m on a flat road if the coefficient of fricti

RideAnS [48]

Answer:

Maximum speed of the car is 26.56 m/s.

Explanation:

Given that,

Mass of the car, m = 1200 kg

Radius of the curve, r = 90 m

The coefficient of friction between tires and the road is 0.8.

We need to find the maximum speed of the car. On the circular curve, the centripetal force is balanced by the force of friction. So,

$\dfrac{v^2}{r}=\mu g\\\\v=\sqrt{\mu gr} \\\\v=\sqrt{0.8\times 9.8\times 90} \\\\v=26.56\ m/s$

So, the maximum speed of the car is 26.56 m/s.

5 0

4 years ago

At a certain elevation, the pilot of a balloon has a mass of 120 lb and a weight of 119 lbf. What is the local acceleration of g

Strike441 [17]

Answer:

31.905 ft/s²

Explanation:

Given that

Mass of the pilot, m = 120 lb

Weight of the pilot, w = 119 lbf

Acceleration due to gravity, g = 32.05 ft/s²

Local acceleration of gravity of found by using the relation

Weight in lbf = Mass in lb * (local acceleration/32.174 lbft/s²)

119 = 120 * a/32. 174

119 * 32.174 = 120a

a = 3828.706 / 120

a = 31.905 ft/s²

Therefore, the local acceleration due to gravity at that elevation is 31.905 ft/s²

3 0

3 years ago

I'll Vote Brainliest

aliina [53]

B) only in animal cells

8 0

3 years ago

On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 81.7 cm and diameter 2.70 cm fr

Genrish500 [490]

Answer:

35.792 N

Explanation:

d = Diameter of rod = 2.7 cm

h = Length of rod = 81.7 cm

$\rho$ = Density of rod = 7800 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

Volume of rod

$V=\dfrac{1}{4}\pi d^2h\\\Rightarrow V=\dfrac{1}{4}\times \pi\times (2.7\times 10^{-2})^2\times 81.7\times 10^{-2}$

Mass is given by

$m=\rho V\\\Rightarrow m=7800\times \dfrac{1}{4}\times \pi\times (2.7\times 10^{-2})^2\times 81.7\times 10^{-2}\\\Rightarrow m=3.6486\ kg$

Weight is given by

$W=mg\\\Rightarrow W=3.6486\times 9.81\\\Rightarrow W=35.792\ N$

The weight of the rod is 35.792 N

7 0

3 years ago