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2 years ago

HELP PLEASE I need to finish this asap

Physics

2 answers:

ELEN [110]2 years ago

6 0

Answer:

I'm not 100% sure, but I think the answer would be the first one because there's a force pushing the object in every direction, so they would cancel eachother out and make the object stay in the same place.

Explanation:

pls vote brainliest

kiruha [24]2 years ago

4 0

Third one bro I know this already

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How long does it take for changed in an ecosystem to be reversed

rusak2 [61]

That certain change from that ecosystem will require 50 years or longer because big ecosystems need a long time to restablize the living ecosystem.

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3 years ago

What level of nitrates is considered clean water?

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3 years ago

Find the unknown mass of the block 1 needed to balance the bar. Assume that the mass of the bar is negligible. Block 1 is locate

Natasha2012 [34]

Answer:

Incomplete question: The masses of the blocks m₂ = 1.5 kg and m₃ = 2 kg

Explanation:

Given data:

L₁ = length = 0.85 m

L₂ = 0.25 m

L₃ = 0.5 m

m₂ = 1.5 kg

m₃ = 2 kg

Question: Find the unknown mass of the block 1 needed to balance the bar, m₁ = ?

The torque is zero (intermediate point of the bar)

$-m_{1} gL_{1} +m_{2} gL_{2} +m_{3} gL_{3} =0$

Is negative because mass 1 is to the left of the coordinate system (see the diagram)

$m_{1} =\frac{m_{2} gL_{2}+m_{3} gL_{3} }{L_{1} } =\frac{(1.5*0.25)+(2*0.5)}{0.85} =1.6176kg$

4 0

3 years ago

¿Qué distancia recorre un móvil que lleva una aceleración de 5m/s durante 10seg?

coldgirl [10]

Answer:

250 m

Explanation:

The car in this problem is moving of uniform accelerated motion, so we can use the following suvat equation:

$s=ut+\frac{1}{2}at^2$

where

s is the distance covered

u is the initial velocity

t is the time

a is the acceleration

Assuming the car starts from rest,

u = 0

Also we know that

a = 5 m/s^2 (acceleration of the car)

t = 10 s

Substituting, we find the distance covered:

$s=0+\frac{1}{2}(5)(10)^2=250 m$

3 0

2 years ago

A red train traveling at 72 km/hr and a green train traveling at 144 km/hr are headed toward one another along a straight level

Temka [501]

First, convert all the km/hr into m/s

You will get that
initial speed = 20 m/s
Initial speed of Green train = 40 m/s
Initial separation = 950 m
Velocity of approach = 20 - -40 = 60 m/s
relative acceleration = -4 m/s^2

v = u + at
0 = 60 - 4t

t = 15s

s = ut + 1/2 *at * t

s = 60 * 15 - 1/2 *4 * 225
s = 900 - 450

Separation when they stop = 450 m

hope this helps

5 0

3 years ago