Length of missing leg = 12 km
Using Pythagoras theorem
a² = 15² - 9²
a = √ 225 - 49
a = √144
a = 12 km
HOPE IT HELPS..
Answer:
D. 3 and -4
Step-by-step explanation:
Given the expression, x² - x - 12, let's factorise to find the value of p and q using the table, for which we would have the expression simplified as (x + p)(x + q)
From the table, let's find the values of p and q that would give us -12 when multiplied together, and would also give us -1 when summed together.
Thus, from the table given, the row containing the values of p(3) and q(-4) gives us = -1 (p+q) . p = 3, q = -4 would be our values to use to factor x² - x - 12, as multiplying both will also give us "-12".
Thus, x² - x - 12 would be factorised or simplified as (x + 3)(x - 4)
Therefore, the answer is: D. 3 and -4
Tbh it’s 600$ bc lol i the only thing u know ??
the coordinates of endpoint B are (7,7)
Answer:
Solution given:
M(x,y)=(2,-1)
A
Let
B
now
by using mid point formula
x=
$ubstituting value
2*2=-3+a
a=4+3
a=7
again
y=
$ubstituting value
-1*2=5-b
b=5+2
b=7
the coordinates of endpoint B are (7,7)
Using the data for each truck lets calculate,
median for truck 1 - 511.5
median for truck 2 - 650.5
lets consider each statement
A.medians for both trucks are the same - wrong
median for 1 and 2 are 511.5 and 650.5 respectively
B. the two trucks sold most number of tacos on 3rd day
truck 1 sold 437 on day 3 but highest number it sold was 721 on day 1
truck 2 sold 426 on day 3 but highest number was 732 on day 6
therefore this statement too is wrong
C.
truck 1 - range between maximum(721) and minimum(425) = 296
truck 2 - maximum (732) and minimum (426) difference = 306
the range between maximum and minimum in truck 2 is 306 thats greater than range between maximum and minimum in truck 1, that's 296
therefore this statement is correct
D.
total number of tacos for each truck -
truck 1 - 5291
truck 2 - 6107
food truck 1 sold less than truck 2 therefore this statement too is wrong
