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Gnom [1K]
2 years ago
5

A spring with a spring constant

Physics
1 answer:
Masteriza [31]2 years ago
7 0
1.76N
should be correct
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I just need x isolated
mamaluj [8]

Answer:

x=\frac{-y+\sqrt{y^2+4rt} }{2r}

x=\frac{-y-\sqrt{y^2+4rt} }{2r}

Explanation:

rx+y=\frac{t}{x}\\\\x(rx+y)=(\frac{t}{x})x\\\\rx^2+yx=t\\\\rx^2+yx-t=t-t\\\\rx^2+yx-t=0

Solve using the quadratic formula.

x=\frac{-y+\sqrt{y^2+4rt} }{2r}

x=\frac{-y-\sqrt{y^2+4rt} }{2r}

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three resistors which values of 15 ohm 40 ohm 60 ohm respectively are connected in parallel. what is their equivalent resistance
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1) Equivalent resistance, 1/R = 1/15 + 1/40 + 1/60 = 8+3+2 /120 = 13/120

R = 120/13 = 9.23

2) Current, I = V/R = 115/9.23 = 12.45 A



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