Answer:
B) Ksp = 3.7 E-11
Explanation:
CaF2 ↔ Ca2+ + 2F-
S S 2S,,,,,,,,,,,,,,,in the equilibrium
⇒ Ksp = [ Ca2+ ] * [ F- ]²
⇒ Ksp = S * ( 2S )²
⇒ Ksp = 4S³
⇒ Ksp = 4 * ( 0.00021 )³
⇒ Ksp = 4 * 9.261 E-12
⇒ Ksp = 3.704 E-11
I) carbon dioxide
ii) nitrogen dioxide
iii) nitric acid
iv) sulphric acid
v) Potassium dichromate
vi) hexacyanoferrate (III) ion( not sure)
