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raketka [301]
3 years ago
11

The solubility of CaF2 is 0.00021 mole per liter. What is the solubility product constant for CaF2? A) 7.3 x 10-12 B) 3.7 x 10-1

1 C) 8.5 x 10-8 D) 4.4 x 10-8 E) 1.9 x 10-11
Chemistry
1 answer:
Naddika [18.5K]3 years ago
3 0

Answer:

B) Ksp = 3.7 E-11

Explanation:

CaF2 ↔ Ca2+  +  2F-

  S            S          2S,,,,,,,,,,,,,,,in the equilibrium

⇒ Ksp = [ Ca2+ ] * [ F- ]²

⇒ Ksp = S * ( 2S )²

⇒ Ksp = 4S³

⇒ Ksp = 4 * ( 0.00021 )³

⇒ Ksp = 4 * 9.261 E-12

⇒ Ksp = 3.704 E-11

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The diatomic molecule of chlorine, cl2, is held together by a(n)____ covalent bond.
kvasek [131]

Answer : The diatomic molecule of chlorine, Cl₂, is held together by a SINGLE covalent bond.

Covalent Bond :

It is type of chemical bond, which is formed by sharing of electron between atoms . The covalent bond is formed between two non metals . The valance electron are shared to form the bond . The shared electrons are known as BONDING electron pair and the electron pair which do not take part in bonding are known as NON- BONDING electron pair. Example : O₂ , H₂ , H₂O, NH₃ etc .

Formation of covalent bond in Cl₂ :

Chlorine is present in group 17 in p block , It is a non metal .

The electronic configuration of Cl is : 1s² 2s² 2p⁶ 3s² 3p⁵ .

Since the outer shell is n= 3 , which has 7 electrons in it , hence Cl has 7 valence electrons in it .

From electronic configuration , it can be seen that Cl need 1 electron to complete its octet (3s² 3p⁶ ). Hence when two Cl atoms come close they share one-one electron with each other (as shown in image ) .

Now the octet of both the atom are complete and they are in stable state together .

When both Cl atom share one e⁻ , there is a bond formed between Cl atoms . One bond consists of 2⁻ . Hence in Cl₂ SINGLE covalent bond present .

Cl + Cl -> Cl₂

7 0
4 years ago
The specific heat capacity of a certain type of cooking oil is 1.75 J/(g⋅∘C). What is the amount of heat exchanged when the temp
anygoal [31]

Answer:

Q = -811440 J

Explanation:

Given data:

Mass of oil = 2.76 Kg (2.76× 1000 = 2760 g)

Initial temperature = 191 °C

Final temperature = 23°C

Specific heat capacity of oil = 1.75 J/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 23°C - 191 °C

ΔT = -168°C

Q = 2760 g ×1.75 J/g.°C  ×-168°C

Q = -811440 J

Negative sign show heat is released.

6 0
3 years ago
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GuDViN [60]

Answer: Yes. That is right. The actual answer, not rounded, would be 12.7778 Degrees Celsius.

7 0
3 years ago
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scZoUnD [109]
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3 0
3 years ago
What is the percentage by mass of nitrogen in the fertiliser (NH4)3PO4? [Ar: H = 1, N = 14, O = 16, P = 31]
BaLLatris [955]

Answer:

(NH4)3PO4 is 28.2 % N , 8.1% H, 20.8 % P and 43.0 % O by mass.

Explanation:

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