We need to first find the molarity of Ba(OH₂) solution.
A mass of 3.24 mg is dissolved in 1 L solution.
Ba(OH)₂ moles dissolved - 3.24 x 10⁻³ g/171.3 g/mol = 1.90 x 10⁻⁵ mol
dissociaton of Ba(OH)₂ is as follows;
Ba(OH)₂ --> Ba²⁺ + 2OH⁻
1 mol of Ba(OH)₂ dissociates to form 2OH⁻ ions.
Therefore [OH⁻] = (1.90 x 10⁻⁵)x2 = 3.8 x 10⁻⁵ M
pOH = -log[OH⁻]
pOH = -log (3.8 x 10⁻⁵)
pOH = 4.42
pH + pOH = 14
therefore pH = 14 - 4.42
pH = 9.58
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Answer:
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Explanation:
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Answer:
C6 H10 O5+ 6O2-----> 6CO2+5H2O+heat
Explanation:
There are 6 carbon atoms in reactants to balance you put coefficient 6.
This makes the oxygen in CO2 12 so to balance put 6 in oxygen in reactants.
There are 10 hydrogen atoms in reactants to balance you put 5 in front of H2O in products.
If u recheck: 6 C atoms in reactants, 6 C atoms in products.
10 H atoms in reactants, 10 H atoms in products.
17 O atoms in reactants, 17 O atoms in products.