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3 years ago

Give two conditions in which an object becomes weightless

Physics

2 answers:

stepan [7]3 years ago

7 0

Answer:

At the time of zero gravity there is no weight and at the time of where is there is no air and there is vaccum there is no weight

Explanation:

Evgesh-ka [11]3 years ago

4 0

Answer:

A body becomes weightless in a zero-gravity scenario and when a force is applied to a body that is equal and opposite to the force of gravity.

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Assume that a resistor is connected between the 150 V terminal and the common terminal. The voltmeter is then connected to an un

Lena [83]

Answer: $316.8V$

Explanation:

given data:

metre moving current = $0.96mA$

meters voltage = $288V$

or $0.96*300V = 288V$

Solution:

$v1 = (0.96mA*150)$

$= 144V$

$i1 = \frac{144v}{750}$

$= 0.192mA$

$i2 = imovement + i1$

$i2= 0.96mA+0.192mA$

$= 1.152mA$

$Vmeasured = 144V+(150)(1.152mA)$

$=316.8V$

the unknown voltage is 316.8V

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3 years ago

The rings of Saturn occupy the region inside Saturn's Roche limit.

Oliga [24]

I suppose this is a true or false question and that sentence is true.

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3 years ago

Multiply the following numbers, using scientific notation and the correct amount of significant digits. 1.003 m⋅3.09 = _____ 3.0

lozanna [386]

Answer

correct answer is 3.10

Explanation:

in this question we have to multiply two numbers 1.003 and 3.09.

1.003 has 4 significant digits and 3.09 has 3 significant digits so answer must have 3 significant digits.

$1.003\times 3.09=3.09927$

$1.003\times 3.09=3.10$

Hope it will help you

3 0

2 years ago

Read 2 more answers

Mr. Smith used 606 kWh for the month. If the service charge was $61.37 (see back page of the bill), what is the approximate char

Murrr4er [49]

Answer:

.10/KWh

Explanation:

divide 606 by 61.37 and you get .1012...

7 0

3 years ago

How do I solve this step by step? I’m really confused

LekaFEV [45]

Step-#1:

Ignore the wire on the right.

Find the strength and direction of the magnetic field at P,

caused by the wire on the left, 0.04m away, carrying 5.0A

of current upward.

Write it down.

Step #2:

Now, ignore the wire on the left.

Find the strength and direction of the magnetic field at P,

caused by the wire on the right, 0.04m away, carrying 8.0A

of current downward.

Write it down.

Step #3:

Take the two sets of magnitude and direction that you wrote down

and ADD them.

The total magnetic field at P is the SUM of (the field due to the left wire)

PLUS (the field due to the right wire).

So just calculate them separately, then addum up.

4 0

3 years ago

Give two conditions in which an object becomes weightless​

Give two conditions in which an object becomes weightless