The molar heat of vaporization of ammonia is 23.3 kJ/mol. The molar heat of condensation of ammonia is - 23.3 kJ/mol.
The molar heat of condensation is the opposite of the molar heat of vaporization. The molar heat of vaporization of ammonia is given :
ΔH evaporation = - ΔH condensation
Therefore the molar heat of condensation of ammonia is given by:
ΔH condensation = - 23.3 kJ / mol
That's right. The molar heat of vaporization of ammonia is 23.3 kJ/mol. The molar heat of condesation of ammonia is - 23.3 kJ/mol.
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A 3.4 × 10⁶ L swimming pool must have a mass of 1.0 × 10⁷ mg Cl₂ to maintain a concentration of 3.0 ppm.
<h3>What is "ppm"?</h3>
"ppm" of "parts per million" is a unit of concentration equivalent to milligrams of solute per liters of solution.
A pool must maintain a chlorine concentration of 3.0 ppm (3.0 mg/L). The mass of chlorine in 3.4 × 10⁶ L is:
3.0 mg Cl₂/L × 3.4 × 10⁶ L = 1.0 × 10⁷ mg Cl₂
A 3.4 × 10⁶ L swimming pool must have a mass of 1.0 × 10⁷ mg Cl₂ to maintain a concentration of 3.0 ppm.
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The polar bear lives in a cold artic tundra, whereas butterflys live in sunny tropical areas, they are different because the locations and tempuratures are different.
<h3>Heya</h3><h3>Here is your answer</h3><h3>________________</h3><h3></h3><h3>A temperature of 20°C is equivalent to approximately 68 degree Fahrenheit (standard room temperature).</h3><h3></h3><h3>==================</h3><h3></h3><h3>Hope this helped!!!</h3><h3>Happy to help :)</h3>
Answer:
5.0 %
Explanation:
Given data
- Volume of ethylene glycol (solute): 50 mL
- Volume of water (solvent): 950 mL
Step 1: Calculate the volume of solution
If we assume that <em>the volumes are additive</em>, the volume of the solution is equal to the sum of the volume of the solute and the solvent.
V = 50 mL + 950 mL = 1000 mL
Step 2: Calculate the percent by volume
We will use the following expression.