Answer:
1,000 N
Explanation:
Force exerted by the bullet on the rifle = 
F = 1000N
Contextual Way:
Newton's second law of motion.
F=m a
Now to solve based on the current info, we shall assume that:-
The force exerted on the bullet was uniform across the entire duration of bullet leaving the barrel, i.e., 0.003 seconds {Not necessarily true for real life applications as the force will not be uniform from the point of hammer impact till the point of leaving the barrel. In reality you will get a Force profile across that entire duration}
We are not distinguishing between bullet and cartridge. {What you shall hold in your hand and load in a revolver is a cartridge containing the gunpowder, bullet etc. The bullet is the projectile at the mouth of the cartridge that actually leaves the barrel and hit the target. So when you are weighing in real life, you are not weighing the bullet, rather the cartridge as a whole}
Getting back to the question
Impulse equation for the bullet
∫F∗dt=∫m∗dv
Average impulse delivered= Change in momentum of the bullet
Assuming average force delivery
Favg∗∫dt=m∗∫dv
Favg∗0.003=0.010∗300
Favg=300∗10/3
Favg=1000N
Answer:
sounds like limestone
Explanation:
but the answer is sedimentary they stick together like cemnt try to remember sedimentary as like cement sedimentary
Answer:
a) The specific heat capacity means the amount of heat needed by a unit mass of a material to increase its temperature in one unit.
b) Liquid P - 
, Liquid Q - 
, Liquid R - 
, Liquid S - 
Explanation:
a) The specific heat capacity means the amount of heat needed by a unit mass of a material to increase its temperature in one unit.
b) Let suppose that heat transfer rates between liquids and surroundings are stable. The quantity of the heat released is determined by the following expression:
(1)
Where:
- Mass of the liquid, in kilograms.
- Specific heat capacity, in joules per kilogram-degree Celsius.
- Initial temperature of the sample, in degrees Celsius.
- Freezing point, in degrees Celsius.
Liquid P (
, 
, 
, 
)
Liquid Q (, 
, , 
)
Liquid R (, 
, , 
)
Liquid S (, 
, , 
)
Answer:
v = 5.34[m/s]
Explanation:
In order to solve this problem, we must use the theorem of work and energy conservation. This theorem tells us that the sum of the mechanical energy in the initial state plus the work on or performed by a body must be equal to the mechanical energy in the final state.
Mechanical energy is defined as the sum of energies, kinetic, potential, and elastic.
E₁ = mechanical energy at initial state [J]
In the initial state, we only have kinetic energy, potential energy is not had since the reference point is taken below 1.5[m], and the reference point is taken as potential energy equal to zero.
In the final state, you have kinetic energy and potential since the car has climbed 1.5[m] of the hill. Elastic energy is not available since there are no springs.
E₂ = mechanical energy at final state [J]
Now we can use the first statement to get the first equation:
where:
W₁₋₂ = work from the state 1 to 2.
where:
h = elevation = 1.5 [m]
g = gravity acceleration = 9.81 [m/s²]
![58 = v^{2} +29.43\\v^{2} =28.57\\v=\sqrt{28.57}\\v=5.34[m/s]](https://tex.z-dn.net/?f=58%20%3D%20v%5E%7B2%7D%20%2B29.43%5C%5Cv%5E%7B2%7D%20%3D28.57%5C%5Cv%3D%5Csqrt%7B28.57%7D%5C%5Cv%3D5.34%5Bm%2Fs%5D)
Answer:
(A) Velocity will be 1.88 m/sec
(b) Force will be 187.45 N
Explanation:
We have given work done = 4780 j
Distance d = 25.5 m
(A) Mass of the truck m = 
We know that kinetic energy is given by
So 
(B) We know that work done is given by
W = Fd
So 
