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algol [13]
3 years ago
9

An electric field of 2.09 kV/m and a magnetic field of 0.358 T act on a moving electron to produce no net force. If the fields a

re perpendicular to each other, what is the electron's speed?
Physics
1 answer:
My name is Ann [436]3 years ago
8 0

Answer:

The velocity is  v =  5838 \ m/s

Explanation:

From the question we are told that

   The electric field is E  =  2.09 kV/m =  2.09 *10^{3} \ V/m

    The magnetic field is  B  =  0.358 \ T

     

Generally the force experienced by the electron due to the magnetic field is

         F_m  =  qvB

Generally the force experienced by the electron due to the electric  field is

       F_e =  qE

Since from the question the net force is zero  then

     F_e =  F_m

=>    v =  \frac{E}{B}

Substituting values

      v =  \frac{2.09*10^{3}}{0.358 }

    v =  5838 \ m/s

     

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Vector A has a magnitude of 8.0 m and points east, vector B has a magnitude of 6.0 m and points north and vector C has a magnitu
sineoko [7]

Answer:

The answer is E) 6.7m at an angle 63° north of east

Explanation:

We begin by writing out our given vectors A,B and C in their respective rectangular Cartesian coordinate form. which are given as A=8i, B=6j and C= -5j (negative because it points towards west which is towards the left which is taken as the negative direction).Now we simply add all three to obtain our final vector given by,

V=A+B+C\\V=8i + 6j - 5i\\V=3i + 6j

In the last step we just added the like components. Now we will have to calculate the magnitude and angle of V(with respect of the east direction), which is given by,

|V| = \sqrt{3^2 + 6^2} =6.7m\\\\\alpha =tan^{-1} (6/3)=tan^{-1} (2) = 63.4

the angle alpha is always calculated with respect to the horizontal positive axis, and since both components of the vector are positive the vector lies in the first quadrant. Hence the 63° angle north of east is justified. The term north of east means the angle formed in moving from east towards the north that is from the positive horizontal axis to the positive vertical axis.

8 0
4 years ago
6. Mithra is an unknown planet that has two airless moons. A and B, in circular orbits around it.
Ainat [17]

The acceleration of gravity on Moon B is D) 0.25 m/s2

Explanation:

The data listed in the problem are not clear: find them in the table attached.

The acceleration of gravity on a planet is given by the following equation:

g=\frac{GM}{R^2}

where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

M is the mass of the planet

R is the radius of the planet

Here we want to find the acceleration of gravity on the surface of Moon B, which has the following data:

M=1.5\cdot 10^{20} kg (mass)

R=2.0\cdot 10^5 m (radius)

And substituting into the equation, we find:

g=\frac{(6.67\cdot 10^{-11})(1.5\cdot 10^{20})}{(2.0\cdot 10^5)^2}=0.25 m/s^2

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4 0
3 years ago
BRAINLIEST!
Vlada [557]

The two tests used for measuring each of the following fitness areas are as follows:

     a) Cardiorespiratory fitness → The 2.4 km run test; Astrand treadmill test

     b) Muscle strength → Muscle Testing Scale,  Bench/Leg press

     c) Body Composition → DEXA Scan, Bioelectrical Impedance Analysis

      Cardiorespiratory fitness is the ability of the circulatory as well as the respiratory systems to deliver oxygen to the mitochondria of skeletal muscle for energy generation during physical activity.

     

      Cardiorespiratory fitness is a vital indicator of both physical and mental wellbeing. It can lower the chance of developing heart disease and type 2 diabetes. Cardiorespiratory fitness improves lung and heart health while also increasing emotions of well-being.

  • The astrand treadmill test is used widely for testing the fitness of cardiorespiratory. The usefulness of this test is used to assess a client's aerobic fitness.
  • The 2.4 km run test is an uncomplicated running test that needs the use of a stopwatch and a running track. It is widely used for aerobic fitness

      Muscle strength refers to the capacity to move and lift items.  It is determined by the amount of power you can exert and the amount of weight you can lift within a short amount of time.

   

      The test used to determine the muscle strength can be:

  • Muscle Testing Scale;
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     Muscular strength testing is used to examine a complaint of weakness, which is common when there is a suspectable neurologic illness or muscle imbalance.

 

      Bench presses are weight-training exercises that can be added to your routine to help increase upper body strength and improve muscular endurance.

      Body Composition relates to the bones, muscles, and body fat in the body. Body physique composition is used by medical professionals to determine if you are at a healthy weight for your specific body.

       The test used to determine the body Composition can be:

  • DEXA Scan
  • Bioelectrical Impedance Analysis  

        Dexa Scan scans your body using x-ray technology to offer a thorough evaluation of the amount of muscle mass and fat mass your body contains, as well as where fat and muscle are deposited or stored on your body.

        Bioelectrical Impedance Analysis evaluates fat-free mass by passing a low electric current across the body. Because electricity can only move by water, and each body tissue includes variable quantities of water, the conductivity of each tissue type influences the flow of the electric current. 

Therefore, from the above explanations, we can conclude that we've clearly understood the various test for each fitness area.

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8 0
3 years ago
A force of 5 N accelerates an object. The object’s mass is 50 g. What is the acceleration of the object? (Formula: F=ma)
natima [27]

Explanation:

F = ma

5 N = (0.050 kg) a

a = 100 m/s²

3 0
4 years ago
A rocket ship has several engines and thrusters. While the Solid Rocket Booster (SRB) and main engines only work together during
Alexeev081 [22]

The acceleration of the SRB and main engine during the first 2.0 minutes of flight is 52.16 m/s².

The given parameters;

  • <em>initial velocity of the engine, u = 1341 m/s</em>
  • <em>final velocity of the engine, v = 7600 m/s</em>
  • <em>time of motion, t = 2 minutes = 2 x 60 s = 120 s</em>

The acceleration of the SRB and main engine is calculated as follows;

a = \frac{\Delta v}{\Delta t } \\\\a = \frac{7600 - 1341}{2 \times 60  s} \\\\a = 52.16 \ m/s^2

Thus, the acceleration of the SRB and main engine during the first 2.0 minutes of flight is 52.16 m/s².

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4 0
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