Question

An electric field of 2.09 kV/m and a magnetic field of 0.358 T act on a moving electron to produce no net force. If the fields are perpendicular to each other, what is the electron's speed?

Answer 1

Answer:

The velocity is  $v = 5838 \ m/s$

Explanation:

From the question we are told that

   The electric field is $E = 2.09 kV/m = 2.09 *10^{3} \ V/m$

    The magnetic field is  $B = 0.358 \ T$

     

Generally the force experienced by the electron due to the magnetic field is

         $F_m = qvB$

Generally the force experienced by the electron due to the electric  field is

       $F_e = qE$

Since from the question the net force is zero  then

     $F_e = F_m$

=>    $v = \frac{E}{B}$

Substituting values

      $v = \frac{2.09*10^{3}}{0.358 }$

    $v = 5838 \ m/s$