The correct answer is C.
Most of the time, double replacements produce one product that is soluble and one that is insoluble
This results in a precipitate within a liquid or aqueous solution
Hope this helps
Explanation:
this is your answer hope it will help you
Answer : 17.12 g
Explanation:
= elevation in boiling point
= boiling point elevation constant
m= molality

given 
Molar mass of solute = 46.0 
Weight of the solvent = 150.0 g = 0.15 kg
Putting in the values


x = 17.12 g
<h3>
Answer:</h3>
19.3 g/cm³
<h3>
Explanation:</h3>
Density of a substance refers to the mass of the substance per unit volume.
Therefore, Density = Mass ÷ Volume
In this case, we are given;
Mass of the gold bar = 193.0 g
Dimensions of the Gold bar = 5.00 mm by 10.0 cm by 2.0 cm
We are required to get the density of the gold bar
Step 1: Volume of the gold bar
Volume is given by, Length × width × height
Volume = 0.50 cm × 10.0 cm × 2.0 cm
= 10 cm³
Step 2: Density of the gold bar
Density = Mass ÷ volume
Density of the gold bar = 193.0 g ÷ 10 cm³
= 19.3 g/cm³
Thus, the density of the gold bar is 19.3 g/cm³