Question

Calculate the hydroxide ion concentration in an aqueous solution with a poh of 9.85 at 25°c.

Answer 1

 The  hydrogen ion concentration  is  calculated  as follows

Ph  +  POh  =14
ph= 14-9.85= 4.15

anti  -H+

=anti (-4.15)  = 7.07 x10^-5  moles per liter

Answer 2

Answer: The hydroxide ion concentration in aqueous solution is $1.412\times 10^{-10}M$

Explanation:

To calculate the hydroxide ion concentration, we use the equation:

$pOH=-\log[OH^-]$

We are given:

pOH = 9.85

Putting values in above equation, we get:

$9.85=-\log[OH^-]$

$[OH^-]=10^{-9.85}=1.412\times 10^{-10}M$

Hence, the hydroxide ion concentration in aqueous solution is $1.412\times 10^{-10}M$