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Troyanec [42]
4 years ago
8

Calculate the hydroxide ion concentration in an aqueous solution with a poh of 9.85 at 25°c.

Chemistry
2 answers:
LenaWriter [7]4 years ago
7 0
 The  hydrogen ion concentration  is  calculated  as follows

Ph  +  POh  =14
ph= 14-9.85= 4.15

anti  -H+

=anti (-4.15)  = 7.07 x10^-5  moles per liter
Marysya12 [62]4 years ago
6 0

<u>Answer:</u> The hydroxide ion concentration in aqueous solution is 1.412\times 10^{-10}M

<u>Explanation:</u>

To calculate the hydroxide ion concentration, we use the equation:

pOH=-\log[OH^-]

We are given:

pOH = 9.85

Putting values in above equation, we get:

9.85=-\log[OH^-]

[OH^-]=10^{-9.85}=1.412\times 10^{-10}M

Hence, the hydroxide ion concentration in aqueous solution is 1.412\times 10^{-10}M

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Calcium hypochlorite, Ca(OCl)2, is a bleaching agent produced from sodium hydroxide, calcium hydroxide, and chlorine. Socium chl
bija089 [108]

Answer:  The missing coefficient is 2.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

2NaOH+Ca(OH)_2+2Cl_2\rightarrow Ca(OCl)_2+2NaCl+2H_2O

As in the products, there are 2 atoms of sodium, thus there will be 2 atoms of  of sodium in the reactant as well.  This will balance the number of hydrogen and oxygen atoms as well.

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6 0
3 years ago
Keq for the reaction below is 2400. If the initial conditions of the reaction are a 1.0 L flask that contains 0.024 mol NO (g),
podryga [215]

Answer:

The answer to your question is it is not at equilibrium, it will move to the products.

Explanation:

Data

Keq = 2400

Volume = 1 L

moles of NO = 0.024

moles of N₂ = 2

moles of O₂ = 2.6

Process

1.- Determine the concentration of reactants and products

[NO] = 0.024 / 1 = 0.024

[N₂] = 2/1 = 2

[O₂] = 2.6/ 1= 2.6

2.- Balanced chemical reaction

                     N₂ + O₂    ⇒   2NO

3.- Write the equation for the equilibrium of this reaction

                     Keq = [NO]²/[N₂][O₂]

- Substitution

                    Keq = [0.024]² / [2][2.6]

-Simplification

                    Keq = 0.000576 / 5.2

-Result

                    Keq = 1.11 x 10⁻⁴

Conclusion

It is not at equilibrium, it will move to the products because the experimental Keq was lower than the Keq theoretical-

                         1.11 x 10⁻⁴ < 2400

7 0
3 years ago
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