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3 years ago

Find the voltage across the 15 Ohm resistor plz help ty

Physics

1 answer:

jonny [76]3 years ago

7 0

Answer:

5.4 Volts is the answer!

Explanation:

Good luck with Acellus!

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A volleyball dug out by the opponent popped straight up into the air. It takes 2.05 seconds for the ball to reach its peak. Dete

Archy [21]

Answer:

The height to which the ball flies is 86.6 m.

Explanation:

Given that,

Time = 2.05 sec

Acceleration = 9.8 m/s²

We need to calculate the initial velocity of volleyball

Using equation of motion

$v=u-at$

Where, u = initial velocity

a = acceleration

t = time

Put the value into the formula

$0=u-9.8\times(2.05)^2$

$u=41.2\ m/s$

We need to calculate the height of the the ball

Using equation of motion

$v^2=u^2-2ah$

Put the value into the formula

$0=(41.2)^2-2\times9.8\times h$

$h=\dfrac{(41.2)^2}{2\times9.8}$

$h=86.6\ m$

Hence, The height to which the ball flies is 86.6 m.

6 0

4 years ago

The gravitational force between two objects is 1600 N. What will be the gravitational force between the objects if the distance

goldfiish [28.3K]

3200 N
1600X2= 3200
It doubles so you multiply 3200 by 2

7 0

3 years ago

What must happen to the electrons in a material to create an electric current?

zhenek [66]

You have to have electrons that are in the materials conduction band. Then you apply a voltage across the material.

8 0

4 years ago

Read 2 more answers

Helium gas at 20 °C is confined within a rigid vessel. The gas is then heated until its pressure is doubled. What is the final t

victus00 [196]

Answer:

586 K

Explanation:

Let P is the initial pressure.

Initial temperature, T₁ = 20°C = 293 K

Final pressure, P₂ = 2P

We need to find the final temperature of the gas.

The relation between the pressure and the temperature is as follows

$P\propto T\\\\or\\\\\dfrac{P_1}{P_2}=\dfrac{T_1}{T_2}$

Put all the values,

$\dfrac{P}{2P}=\dfrac{293}{T_2}\\\\\dfrac{1}{2}=\dfrac{293}{T_2}\\\\T_2=2\times 293\\\\T_2=586\ K$

So, the final temperature of the gas is 586 K.

4 0

3 years ago

The elementary particle called a muon is unstable and decays in about 2.20μs2.20μs , as observed in its rest frame, into an elec

vredina [299]

Answer:

5.865 μs

Explanation:

t₀ = Time taken to decay a muon = 2.20 μs

c = Speed of Light in vacuum = 3×10⁸ m/s

v = Velocity of muon = 0.927 c

t = Lifetime observed

Time dilation

$t=\frac{t_0}{\sqrt{1-\frac{v^2}{c^2}}}\\\Rightarrow t=\frac{2.2\times 10^{-6}}{\sqrt{1-\frac{(0.927c)^2}{c^2}}}\\\Rightarrow t=\frac{2.2\times 10^{-6}}{\sqrt{1-0.927^2}}\\\Rightarrow t=\frac{2.2\times 10^{-6}}{\sqrt{0.140671}}\\\Rightarrow t=\frac{2.2\times 10^{-6}}{0.3750}\\\Rightarrow t=5.865\times 10^{-6}\ seconds$

∴Lifetime observed for muons approaching at 0.927 the speed of light is 5.865 μs

3 0

3 years ago