1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leya [2.2K]
3 years ago
7

The more ______ an object moves, the more __________ it has (Kinetic Energy)

Physics
1 answer:
belka [17]3 years ago
3 0

Answer:

__________

Explanation:

You might be interested in
As a quality test of ball bearings, you drop bearings (small metal balls), with zero initial velocity, from a height of 1.94 m i
11Alexandr11 [23.1K]

Answer:

The average acceleration of the bearings is 0.77\times10^{3}\ m/s^2

Explanation:

Given that,

Height = 1.94  m

Bounced height = 1.48 m

Time interval t=14.86\times10^{-3}\ s

Velocity of the ball bearing just before hitting the steel plate

We need to calculate the velocity

Using conservation of energy

mgh=\dfrac{1}{2}mv^2

Put the value into the formula

9.8\times1.94=\dfrac{1}{2}\times v^2

v=\sqrt{2\times9.8\times1.94}

v=6.166\ m/s

Negative as it is directed downwards

After bounce back,

We need to calculate the velocity

Using conservation of energy

mgh=\dfrac{1}{2}mv^2'

Put the value into the formula

9.8\times1.48=\dfrac{1}{2}\times v^2'

v'=\sqrt{2\times9.8\times1.48}

v'=5.38\ m/s

We need to calculate the average acceleration of the bearings while they are in contact with the plate

Using formula of acceleration

a=\dfrac{v-v'}{t}

Put the value into the formula

a=\dfrac{5.38-(-6.166)}{14.86\times10^{-3}}

a=776.98\ m/s^2

a=0.77\times10^{3}\ m/s^2

Hence,The average acceleration of the bearings is 0.77\times10^{3}\ m/s^2

6 0
3 years ago
State two ways of reducing the drag forces on a bicycle
Eddi Din [679]
I am quite sure the first one is Friction, but I am not sure about the second one. Is it wind?
7 0
3 years ago
Releases hydrogen ions in water is that acid or bases?
wolverine [178]
Acid it is i believe........
6 0
3 years ago
Two fishing boats depart a harbor at the same time, one traveling east, the other south. the eastbound boat travels at a speed 1
Novosadov [1.4K]
<span>they are travelling at right angles to each other.
 At any given instant they form a right triangle with their starting point
 </span>South bound <span>= x  [mi/h]
</span> East bound <span> = x+1 [mi/h]
 after five hours they will be
 d=5x
 and
 d=5(x+1)
 miles away from the starting point 
 (5x)^2+(5(x+1))^2=625
 25x^2+(5x+5)^2=625
 25x^2+25x^2+50x+25=625
 50</span>x^2+50x-600=0
<span> x^2+ x - 12=0
 (x+4)(x-3)=0
 take the postive value
 x= 3 mph the speed of south bound
 4mph east bound </span>
6 0
3 years ago
What is gravity’s role in tides?
kotegsom [21]

The relationship between the masses of the Earth, moon and sun and their distances to each other play critical roles in affecting tides

6 0
3 years ago
Read 2 more answers
Other questions:
  • Which substance is used to remove rust from metal?
    11·2 answers
  • If we relied solely on the nonrenewable resources found in the U.S., which one would we run out of first at current usage levels
    5·2 answers
  • What is the magnitude of the net torque on the pulley about the axle?
    10·1 answer
  • Why are some animals and plants can become pests when introduced into Australia
    14·1 answer
  • Write a paragraph that explains how one gene can be responsible for many traits, and how how many genes can be responsible for o
    11·1 answer
  • How much force does a soccer goalie
    9·1 answer
  • Why are ionized gases typically only found in very high-temperature environments?
    12·1 answer
  • Calculate the mass of a liter of water in grams.
    14·1 answer
  • Help meee!! PLZZZZ It's worth 20 points and if you get it right I will mark brainlist.
    12·1 answer
  • An object falls from a height of 12m. The object's potential energy at the top is 50J. Where is the potential energy of the obje
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!