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CaHeK987 [17]
3 years ago
8

How many hydrogen atoms are present in a hydrocarbon chain of five carbon atoms with two double bonds and two single bonds?

Chemistry
1 answer:
VashaNatasha [74]3 years ago
7 0
Is it multiple choice? if not, five.

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Is O2 a element or a compound
Dvinal [7]
O2 is an element As it contains just one kind of atom, O2 is an element,
8 0
3 years ago
Read 2 more answers
How do potential energy diagrams represent energy transfer in<br> chemical reactions?
Digiron [165]

Answer:

Hope this helps

Explanation:

Potential energy diagrams represent the energy transfer in chemical reactions  in a diagram called a potential energy graph and/or a reaction progress curve. A potential energy diagram shows the adjustment in potential energy of a system as reactants are changed.

5 0
3 years ago
What is the total number of liters of SO3 produced when 32.0 of SO2 reacts completely
ahrayia [7]
Write  the   chemical  equation   for  reaction
that  is  
2SO2+O2  --->2SO2

find  the   moles  of  SO2   used  =  moles=mass/molar mass  of  so2

=  32g/80g/mol=0.4 moles

by  use  of  reacting  ratio  between  SO2   and  SO3   which   is   2:2  therefore  the  moles  of  so3  is  also =  0.4  moles

STP  1 mole  =  22.4L.
what  about  0.4moles

= 0.4 /1 x22.4=8.96 liters
4 0
3 years ago
Draw a chair conformation for cis-1-bromo-2,4-dimethylcyclohexane showing equatorial and axial positions at the carbon atoms bea
Ahat [919]

Answer:

See attachment.

Explanation:

Mono-substituted cyclohexanes are more stable with their substituents in an equatorial position. However, with poly-substituted cyclohexanes, the situation is more complex since the steric effects of all substituents have to be taken into account. In this case, you can see that <u>the interconversion is shifted towards the conformation in the bottom because there is less tension between the substituents</u>.

6 0
3 years ago
The reactant concentration in a second-order reaction was 0.560 m after 115 s and 3.30×10−2 m after 735 s . what is the rate con
Aloiza [94]
Use the formula for second order reaction:

\frac{1}{C} = \frac{1}{C_0} + kt

C = concentration at time t 
C0 =  initial conc.
k = rate constant
t = time

1st equation :   \frac{1}{0.56} = \frac{1}{C_0} + 115k

2nd Equation: \frac{1}{0.033} = \frac{1}{C_0} + 735k

Find \frac{1}{C_0} from 1st equation and put it in 2nd equation:

\frac{1}{0.033} = \frac{1}{0.56} - 115k + 735k

\frac{1}{0.033} - \frac{1}{0.56} = 620k

k = 0.046
3 0
3 years ago
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