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CaHeK987 [17]
4 years ago
8

How many hydrogen atoms are present in a hydrocarbon chain of five carbon atoms with two double bonds and two single bonds?

Chemistry
1 answer:
VashaNatasha [74]4 years ago
7 0
Is it multiple choice? if not, five.

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How does hybridization of atomic orbitals allow us to reconcile valence bond theory with vsepr theory?.
S_A_V [24]

Hybridization of atomic orbitals produces orbital shapes and spatial orientations that correlate to those predicted in VSEPR theory.

<h3>What is VSEPR theory ?</h3>

The number of electron pairs surrounding an individual molecule's core atoms can be used to forecast a molecule's shape using the chemical model known as the valence shell electron pair repulsion hypothesis. The two principal creators of the theory, Ronald Gillespie and Ronald Nyholm, gave it the additional moniker Gillespie-Nyholm theory.

  • Hybrid orbital theory explains how these forms are created, while VSEPR theory predicts the shapes of molecules. VSEPR theory's central tenet is that electron pairs—both those in bonds and those that are alone repel one another. "Groups" refers to the electron pairs, both in bonds and lone pairs.

Learn more about VSEPR theory here:

brainly.com/question/14225705

#SPJ4

4 0
1 year ago
What are the reactants and products when butane combusts with excess oxygen?
larisa86 [58]
C3H8 + O2 --> CO2(g) + H2O(g) + energy(heat)

butane + oxygen --> carbon dioxide + water + heat 
7 0
3 years ago
What is ΔG° at 298 K for the following equilibrium? Ag+(aq) + 2NH3(aq) Ag(NH3)2+(aq); Kf = 1.7 × 107 at 298 K a. 41 kJ b. 0 c. –
jekas [21]

Answer:

ΔG° = 41.248 KJ/mol (298 K); the correct answer is a) 41 KJ

Explanation:

Ag+(aq)  +  2NH3(aq)  ↔ Ag(NH3)2+(aq)

⇒ Kf = 1.7 E7; T =298K  

⇒ ΔG° = - RT Ln Kf.....for aqueous solutions

∴ R = 8.314 J/mol.K

⇒ ΔG° = - ( 8.314 J/mol.K ) * ( 278 K ) ln ( 1.7 E7 )

⇒ ΔG° = 41248.41 J/mol * ( KJ / 1000J )

⇒ ΔG° = 41.248 KJ/mol

7 0
3 years ago
Read 2 more answers
A solution is made by mixing of water and of acetic acid . Calculate the mole fraction of water in this solution. Be sure your a
Molodets [167]

Answer:

The answer is "0.35".

Explanation:

please find the complete question in the attached file.

Mass of CH_3C0_2 H= 77 \ g \\\\

Molar mass of CH_3C0_2 H = 60.05 \  \frac{g}{mol} \\\\

No of moles in n_{CH_3CO_2H} = 77 \ g \times  \frac{1 \ mol \ CH_3C0_2H}{60.05 \ g}  

                                          = 1.28 \ mol \ CH_3CO_2H

Mass of water (H_2O)= 42 \ g

The molar mass of water (H_2O)= 18.02 \  \frac{g}{mol}

moles of water n_{H_2O}:

= 42 \ g \times \frac{1 mol H_2O}{18.02 \ g} \\\\= 2.33 \ mol \ H_2 O

Molfraction of acetic acid:

X CH_2CO_2H = \frac{n_{CH_3CO_2H}}{n_CH_3CO_2H +n_{H_2}}\\\\

                     =\frac{1.28 \ mol}{1.28 \ mo1 + 2.33 mol}\\\\ = 0.354\\\\= 0.35

7 0
3 years ago
Ten moles of hydrogen are allowed to react with 6 moles of oxygen. How much water will be
Anastaziya [24]

Answer:

10 moles of water are produced,

Explanation:

Given data:

Moles of H = 10 mol

Moles of O = 6 mol

Water obtained = ?

Solution:

Balance chemical equation:

2H₂ + O₂    →    2H₂O

Now we will compare the moles of H₂ and O₂ with water from balance chemical equation.

                            H₂             :          H₂O

                             2              :            2

                             10             :           10

                            O₂             :          H₂O

                             1              :            2

                             6             :           2×6 = 12

Number of moles of water produced by hydrogen are less so hydrogen will be limiting reactant and it will limit the yield of water thus, 10 moles of water are produced.

                                 

3 0
3 years ago
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