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VladimirAG [237]
3 years ago
14

WHICH OF THE FOLLOWING VARIABLES ( WRITTEN IN BOLD) HAVE A PROPORTIONAL RELATIONSHIP????

Mathematics
1 answer:
Bess [88]3 years ago
8 0

Answer:

a

Step-by-step explanation:

ur basically just saying that uts increasing by the same amount when one variable in the equation changes

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chubhunter [2.5K]

Answer:

Dilation

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SOLVE. <br>1/5x=-10<br><img src="https://tex.z-dn.net/?f=1%20%5Cdiv%205x%20%3D%20%20-%2010" id="TexFormula1" title="1 \div 5x =
Sladkaya [172]

Answer: X = -50

Step-by-step explanation:

1. 1/5x = -10

1/5x = -10

2.Multiply by 1

3.Multiply all terms by the same value to eliminate fraction denominators.

4.Simplfiy

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3 years ago
Determine an equation for the right bisector of the line segment with endpoints J(-5,3) and K(3,-2)
Norma-Jean [14]

Answer:

y=1.6x+2.1

Step-by-step explanation:

we know that

The right bisector of the line segment JK is a perpendicular line to the segment JK that pass through the midpoint of segment JK

step 1

Find the midpoint JK

The formula to calculate the midpoint between two points is equal to

M(\frac{x1+x2}{2},\frac{y1+y2}{2})

we have

J(-5,3),K(3,-2)

substitute the values

M(\frac{-5+3}{2},\frac{3-2}{2})

M(\frac{-2}{2},\frac{1}{2})

M(-1,\frac{1}{2})

step 2

Find the slope JK

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have

J(-5,3),K(3,-2)

substitute

m=\frac{-2-3}{3+5}

m=\frac{-5}{8}

m=-\frac{5}{8}

step 3

Find the slope of the line perpendicular to the segment JK

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of the slopes is equal to -1)

m_1*m_2=-1

we have

m_1=-\frac{5}{8}  ----> slope of segment JK

Find m_2

substitute

(-\frac{5}{8})*m_2=-1

m_2=\frac{8}{5}

step 4

Find the equation for the right bisector of the line segment JK

The equation in point slope form is equal to

y-y1=m(x-x1)

we have

m=\frac{8}{5}

point\ M(-1,\frac{1}{2})

substitute

y-\frac{1}{2}=\frac{8}{5}(x+1)

Convert to slope intercept form

isolate the variable y

y-\frac{1}{2}=\frac{8}{5}x+\frac{8}{5}

y=\frac{8}{5}x+\frac{8}{5}+\frac{1}{2}

y=\frac{8}{5}x+\frac{21}{10}

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Write a compound inequality that each graph could represent for the following questions.
ivanzaharov [21]

Answer:

Part 67) x > -2  and x < 3

Part 68) x\leq -1  or  x\geq 1

Step-by-step explanation:

Part 67) we know that

The solution of the number line is the interval -------> (-2,3)

All real numbers greater than -2 and less than 3

so

The compound inequality could be

x > -2  and x < 3

"And” indicates that, both statements must be true at the same time

Part 68) we know that

The solution of the number line is the interval (-∞,-1] ∪ [1,∞)

All real numbers less than or equal to -1 or all real numbers greater than or equal to 1    

The compound inequality could be

x\leq -1  or  x\geq 1

"Or” indicates that, as long as either statement is true, the entire compound sentence is true

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3 years ago
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