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klio [65]
4 years ago
13

Identify the correct same regarding the strength of chemical bonds

Chemistry
1 answer:
bulgar [2K]4 years ago
7 0

Answer:

weak bonds require less energy to form bonds than strong bonds

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What is the mass of an object that has a total heat loss of 550. cal, a specific heat of
Galina-37 [17]

Answer:

the mass is .587 J/g°C

Explanation:

................

4 0
3 years ago
FILL IN THE BLANK. HELPPPP!
Sedbober [7]

Answer :The corrected answer is given below;


Weak bases react with <u>water</u> to form the hydroxide ion and the conjugate <u>acid</u> of the base. Concentration in solution does not affect whether an acid or a base is <u>strong </u>or weak.

The strength of an acid or a base is determined by the <u>dissociation constant</u> of the substance in solution.

The acid dissociation constant, <u>Ka</u>, is a quantitative measure of acid strength. A strong acid has a much <u>higher</u> Ka than a weak acid. The Ka of an acid is determined from measured <u>titration</u> values.


Hydrochloric acid and sulfuric acid are <u>completely</u> ionized in solution and are <u>strong</u> acids. Ethanoic acid, which is only about 1 percent ionized, is a <u>weak</u> acid. Magnesium hydroxide and calcium hydroxide are strong <u>base</u>.

3 0
3 years ago
Read 2 more answers
What is meant by the biodegradability of soap molecules
Flura [38]

Answer:

The biodegradability of soap moleculea means the soap molecules are degradable in nature it doesn't causes water pollution as comparing as detergent.....

4 0
3 years ago
Which of the following substances has the lowest density?
Likurg_2 [28]

Answer:

C) A mass of 750 g and a volume of 70 dL .

Explanation:

Hello,

In this case, for substantiating the substance having the lowest density we need to compute it in the same units for each case as shown below:

\rho=\frac{m}{V}

A) \rho =\frac{1.5kg}{1.2L}*\frac{1000g}{1kg} *\frac{1L}{1000mL}=1.25g/mL

B) \rho =\frac{25g}{20mL}*=1.25g/mL

C) \rho =\frac{750g}{70dL}*\frac{10dL}{1L}*\frac{1L}{1000mL} =0.107g/mL

D) \rho =\frac{15mg}{25\mu L}*\frac{1g}{1000mg} *\frac{1000\mu L}{1mL}=0.6g/mL

Therefore, the lowest density corresponds to C) A mass of 750 g and a volume of 70 dL

Regards.

8 0
3 years ago
You need to produce a buffer solution that has a pH of 4.97. You already have a solution that contains 10. mmol (millimoles) of
motikmotik

Answer:

16.9 mmoles are needed to add to the solution

Explanation:

To solve this, we can apply the Henderson Hasselbach equation:

Acetic acid → CH₃COOH

CH₃COOH  +  H₂O  ⇄  CH₃COO⁻   +  H₃O⁺             Ka

That is the acid base equilibrium, to determine the amount:

pKa of acetic acid is 4.74

Henderson Hasselbach formula is:

pH = pKa + log (base/acid)

We replace  →  4.97 = 4.74 + log (B / 10mmoles)

Let's verify mmoles of B

4.97 - 4.74 = log (B/10)

0.23 =  log (B/10)

10^(0.23) = 10^(log (B/10)

1.698 = B/10

B = 1.698 . 10 → 16.9 mmoles

5 0
3 years ago
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