Ask question

Ask question

All categories

3 years ago

12

I understand what makes a kettle so efficient, but what are some improvements you can make to a kettle to increase it’s energy e

fficiency?

1 answer:

shusha [124]3 years ago

3 0

Answer:

Reheat the cold cup of tea or coffee in the microwave. ...

Make iced tea or coffee with what's left. ...

Use a thermos for either tea or coffee.

You might be interested in

Determine the force of gravity on a 1600 kg spaceship: near the surface of the Moon.

Umnica [9.8K]

Answer:

yahoo has the answer im telling you

Explanation:

3 0

3 years ago

Nikolas had an idea that he could use the compressed carbon dioxide in a fire extinguisher to propel him on his skateboard.

Serggg [28]

Answer:

Newton's third law of motion

Explanation:

Newton's third law of motion: every action has an equal and opposite reaction. Nikolas is using the compressed carbon dioxide to push him on his skateboard. Once the gas is released, it applies force that'll push him in the opposite direction, forward.

4 0

3 years ago

Read 2 more answers

what is the second longest wavelength for a standing wave on a wire with one fixed end and one open end that is 3.0 m long?

olga2289 [7]

Is there any multiple choice answers? Any options?

4 0

3 years ago

A 0.290 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 30.0 pC charge on it

mojhsa [17]

Answer:

Therefore,

The potential (in V) near its surface is 186.13 Volt.

Explanation:

Given:

Diameter of sphere,

d= 0.29 cm

$radius=\dfrac{d}{2}=\dfrac{0.29}{2}=0.145\ cm$

$r = 0.145\ cm = 0.145\times 10^{-2}\ m$

Charge ,

$Q = 30.0\ pC=30\times 10^{-12}$

To Find:

Electric potential , V = ?

Solution:

Electric Potential at point surface is given as,

$V=\dfrac{1}{4\pi\epsilon_{0}}\times \dfrac{Q}{r}$

Where,

V= Electric potential,

ε0 = permeability free space = 8.85 × 10–12 F/m

Q = Charge

r = Radius

Substituting the values we get

$V=\dfrac{1}{4\times 3.14\times 8.85\times 10^{-12}}\times \dfrac{30\times 10^{-12}}{0.145\times 10^{-2}}$

$V=\dfrac{30}{16.117\times 10^{-2}}=186.13\ Volt$

Therefore,

The potential (in V) near its surface is 186.13 Volt.

3 0

4 years ago

How is vibrational motion connected to waves?

frozen [14]

Answer:

Explanation:

Waves and wave functions are direct ways to graph vibrational motion. Specifically, for cases dealing with vibrating strings. If you were to move a tensioned string up and down with your arm, you would produce a wave with a given frequency, period, and amplitude.

3 0

2 years ago