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worty [1.4K]
3 years ago
12

How do you find the angle (to the nearest tenth) on your graph that produced the greatest range, based on the line of best fit?

Physics
1 answer:
VikaD [51]3 years ago
3 0

Answer:

yuououiy

Explanation:

You might be interested in
A 50 kg skater pushes off from a wall with a force of 200 N. What is the skater's acceleration?
lutik1710 [3]

Answer:

Explanation:

mass (m) = 50 kg

Force (F) = 200 N

Acceleration (a)= ?

WE know

F = m * a

200 = 50 * a

a = 200 / 50

a = 4 m/s²

Hope it will help :)

3 0
3 years ago
The driver of a car slams on the brakes, causing the car to slow down at a rate of 17ft/s2 as the car skids 285ft to a stop.
ozzi

1) 5.79 s

2) 98.4 ft/s

Explanation:

1)

The motion of the car is a uniformly accelerated motion (it means it travels with constant acceleration), so we can find the time it takes for the car to stop by using the following suvat equation:

s=vt-\frac{1}{2}at^2

where

s is the distance travelled

v is the final velocity

t is the time

a is the acceleration of the car

In this problem we have:

s = 285 ft is the distance travelled

a=-17 ft/s^2 is the acceleration of the car (negative since the car is slowing down)

v = 0 ft/s is the final velocity of the car, since it comes to a stop

Solving for t, we find:

t=\sqrt{\frac{-2s}{a}}=\sqrt{\frac{-2(285)}{-17}}=5.79 s

2)

The initial speed of the car can be found by using another suvat equation, namely:

v=u+at

where

v is the final speed

u is the initial speed

a is the acceleration

t is the time

In this problem, we have:

v = 0 is the final speed of the car

a=-17 ft/s^2 is the acceleration of the car (negative since the car is slowing down)

t = 5.79 s is the total time of motion (found in part 1)

Therefore, the initial speed of the car is:

u=v-at=0-(-17)(5.79)=98.4 ft/s

8 0
3 years ago
Find a numerical value for rhoearth, the average density of the earth in kilograms per cubic meter. Use 6378km for the radius of
Radda [10]

According to the information provided to define an average density, it is necessary to use the concepts related to mass calculation based on gravitational constants and radius, as well as the calculation of the volume of a sphere.

By definition we know that the mass of a body in this case of the earth is given as a function of

M = \frac{gr^2}{G}

Where,

g= gravitational acceleration

G = Universal gravitational constant

r = radius (earth at this case)

All of this values we have,

g = 9.8m/s^2\\G  = 6.67*10^{-11} m^3/kg*s^2\\r = 6378*10^3 m

Replacing at this equation we have that

M = \frac{gr^2}{G} \\M = \frac{(9.8)(6378*10^3)^2}{6.67*10^{-11}} \\M = 5.972*10^{24}kg

The Volume of a Sphere is equal to

V = \frac{4}{3}\pi r^3\\V = \frac{4}{3} \pi (6378*10^3)^3\\V = 1.08*10^{21}m^3

Therefore using the relation between mass, volume and density we have that

\rho = \frac{m}{V}\\\rho = \frac{5.972*10^{24}}{1.08*10^{21}}\\\rho = 5.52*10^3kg/m^3

6 0
3 years ago
A control is a ____.
Nina [5.8K]
A control is B, standard for comparison. This is used to compare for example plants and using different fertilizers and then have one with no fertilizer. Controls are basically just a base to the entire experiment

I hope this helps you!:)
6 0
3 years ago
I mark brainliest!!!!
densk [106]

Answer:

I think it is False.

Explanation:

I think that a body could not be vertical for every time.

6 0
3 years ago
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