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Basile [38]
3 years ago
6

A pulled tablecloth exerts a frictional force of 0.6 n on a plate with a mass of 0.4 kg. what is the acceleration of the plate?

Physics
1 answer:
Ludmilka [50]3 years ago
6 0
The formula for acceleration is a = F/m; Where: F = force; m = mass
Given: F = .6n; m = .4kg; a = ?
a = F/m
  = .6/.4
  = 1.5

Therefore, the acceleration of the plate is 1.5 m/s^2
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Ic is the rotational inertia of the rod about an axis passing trough its centre of mass and parallel to the rotational axis

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I = (\frac{1}{12})(mL^{2} ) + m([tex]\frac{L}{2})^{2}[/tex]

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I = 0.07875 kg.m^{2}

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   at the maximum height velocity = 0 therefore final kinetic energy = 0

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where (H-h) = rise in the center of mass

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   (H-h) = 0.15 m

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