Answer:
ans: 4.34 × 10^(-9) N
Explanation:
mass of Mya say (m) = 65 kg
mass of spaceship say (M) = 1600 kg
universal gravitational constant(G) =6.67 × 10^(-11) Nm²/kg²
separation distance (d) = 4m
so,
gravitational force (F)= GMm/d²
=( 6.67 × 65 × 1600) / ( 10¹¹ × 4²)
= 4.34 × 10⁴ / 10¹³
= 4.34 × 10^(-9) N
Answer: It prevents us from seeing most of the galactic disk with visible and ultraviolet light.
(hope this helps) :)
Answer:
990 J
Explanation:
Kinetic energy is:
KE = ½ mv²
Given m = 55 kg and v = 6 m/s:
KE = ½ (55 kg) (6 m/s)²
KE = 990 J
Answer:
1. -8.20 m/s²
2. 73.4 m
3. 19.4 m
Explanation:
1. Apply Newton's second law to the car in the y direction.
∑F = ma
N − mg = 0
N = mg
Apply Newton's second law to the car in the x direction.
∑F = ma
-F = ma
-Nμ = ma
-mgμ = ma
a = -gμ
Given μ = 0.837:
a = -(9.8 m/s²) (0.837)
a = -8.20 m/s²
2. Given:
v₀ = 34.7 m/s
v = 0 m/s
a = -8.20 m/s²
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (34.7 m/s)² + 2 (-8.20 m/s²) Δx
Δx = 73.4 m
3. Since your braking distance is the same as the car in front of you, the minimum safe following distance is the distance you travel during your reaction time.
d = v₀t
d = (34.7 m/s) (0.56 s)
d = 19.4 m
