A girl pushes her little brother on his sled with a force of 300 N for 750 m.
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The threshold frequency fo of Cesium is 4.83 × 10¹⁴ Hz
<h3>Further explanation</h3>The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is:
<em>E = Energi of A Photon ( Joule )</em>
<em>h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )</em>
<em>f = Frequency of Eletromagnetic Wave ( Hz )</em>
The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.
<em>E = Energi of A Photon ( Joule )</em>
<em>m = Mass of an Electron ( kg )</em>
<em>v = Electron Release Speed ( m/s )</em>
<em>Ф = Work Function of Metal ( Joule )</em>
<em>q = Charge of an Electron ( Coulomb )</em>
<em>V = Stopping Potential ( Volt )</em>
Let us now tackle the problem!
<u>Given:</u>
Φ = 2.1 eV = 2 × 1.60 × 10⁻¹⁹ Joule = 3.20 × 10⁻¹⁹ Joule
<u>Unknown:</u>
fo = ?
<u>Solution:</u>
- Photoelectric Effect : brainly.com/question/1408276
- Statements about the Photoelectric Effect : brainly.com/question/9260704
- Rutherford model and Photoelecric Effect : brainly.com/question/1458544
- Photoelectric Threshold Wavelength : brainly.com/question/10015690
Grade: High School
Subject: Physics
Chapter: Quantum Physics
Keywords: Quantum , Photoelectric , Effect , Threshold , Frequency , Electronvolt
