Given:
0.060 mol of NiC2O4
Ksp = 4 x 10⁻¹⁰
1.0 L of solution
Kf of Ni(NH3)6 2⁺ = 1.2 x 10⁹
<span>NiC2O4 + 6NH3 ⇋ Ni(NH3)6 2+ + 2O4 2- </span>
<span>NiC2O4 ⇋ Ni 2+ + C2O4 2- ...Ksp </span>
<span>Ni2+ + 6NH3 ⇋ Ni(NH3)6 2+...Kf </span>
Ksp * Kf = (4 x 10⁻¹⁰) * (1.2 x 10⁹) = 0.48
K = 0.48 = [Ni(NH3)6 2+][C2O4 2-] / [NH3]⁶<span>
</span>0.48 = (0.060)² / [NH3]⁶<span> ... (dissolved C2O4 2- = 0.060M)
</span><span>[NH3]</span>⁶<span> = (0.060)</span>²<span> / 0.48 = </span>0.0036 / 0.48 = 0.0075
NH3 = ⁶√0.0075
NH3 = 0.44 M
Answer:
Uranium-233- fission
Plutonium-239- fission
Plutonium-241- fission
Hydrogen-3 fusion
Hydrogen-1 fusion
Helium-3 fusion
Explanation:
In nuclear fission, heavy nuclear disintegrate into smaller nuclei when bombarded with particles such as neutrons. Fission reaction is common among nuclei having a high atomic number such as plutonium and uranium.
Fusion occurs between two light nuclei such as hydrogen or helium. It involves the combination of two lighter elements to give a heavier element with the release of tremendous amount of energy.
The given question is incomplete, here is a complete question.
At 400 K, this Reaction has 
What Is 
at 400 K for the following reaction?
(A) 8.2 x 10⁻⁴
(B) 2.9 x 10⁻²
(C) 6.7 x 10⁻⁷
(D) 1.6 x 10⁻⁷
Answer : The correct option is, (C) 
Explanation :
The given chemical equation follows:
The equilibrium constant for the above equation, .
We need to calculate the equilibrium constant for the following equation of above chemical equation, which is:
, 
The equilibrium constant for the doubled reaction will be the square of the initial reaction.
Or, we can say that
If the equation is multiplied by a factor of '2', the equilibrium constant will be the square of the equilibrium constant of initial reaction.
The value of equilibrium constant for the following reaction is:
Hence, the value of equilibrium constant for the following reaction is,
Answer:
the amswer to number 5 is 18g/ mol and the answer to number 6 is 8
The Answer Is Yes if you guys are doing the (Yes or No ) question
