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3 years ago

What is the change in momentum of a 50. kg woman goes from running at 8.0 m/s to 0.0 m/s?

Physics

1 answer:

oksian1 [2.3K]3 years ago

4 0

Answer:

400 kg-m/s

Explanation:

Given that,

Mass of the woman, m = 50 kg

Initial velocity, u = 8 m/s

Final velocity, v = 0 m/s

We need to find the change in momentum of the woman. It can be given by :

$\Delta p=m(v-u)\\\\=50\times (8-0)\\\\=400\ kg-m/s$

So, the change in momentum is 400 kg-m/s.

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AfilCa [17]

Answer:

different poles

Explanation:

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4 years ago

Read 2 more answers

The x component of vector A is -25.0m and the y component id +40.0m (a) what is the magnitude of A?(b) What is the angle between

Savatey [412]

Answer:

Explanation:

<u>Components of a Vector</u>

A vector in the plane can be defined by its rectangular components:

$\vec A =$

Or also can be given by its polar components:

$\vec A =$

Where r is the magnitude of the vector and θ is the angle it forms with the positive direction of x.

The relation between them is:

$r=\sqrt{x^2+y^2}$

$\displaystyle \theta=\arctan\frac{y}{x}$

It's given the x-component of vector A is x=-25 m and the y-component is y=40 m

(a)

The magnitude of the vector is:

$r=\sqrt{(-25)^2+40^2}$

$r=\sqrt{625+1600}$

$r=\sqrt{2225}$

$r\approx 47.2\ m$

(b)

$\displaystyle \theta=\arctan\frac{40}{-25}$

$\displaystyle \theta=\arctan (-1.6)$

The calculator gives us the value

θ = -58°

But the real angle lies on the second quadrant since x is negative and y is positive, thus:

θ = -58° + 180° = 122°

θ = 122°

8 0

3 years ago

3. A girl is running the 200 m dash. She starts by acceleration at 8m/s^2 for 7s. Then continues at this speed until the end of

antoniya [11.8K]

Answer:

10.6 s

Explanation:

Given that a girl is running the 200 m dash. She starts by acceleration at 8m/s^2 for 7s. Then continues at this speed until the end of the race. How long did it take for her to complete the race?

Solution.

If she accelerated for 7s, the velocity at which she accelerated will be:

Acceleration = velocity/time

8 = V/7

Make V the subject of the formula by cross multiplying.

V = 8 × 7

V = 56 m/s

She maintains the speed through out the journey.

Speed = distance/time

Make time the subject of formula

Time = distance/speed

Time = 200 / 56

Time = 3.57s

Therefore, she will complete the race by 7 + 3.6 = 10.6 s

7 0

3 years ago

Alberta is going to have dinner at her grandmother's house, but she is running a bit behind schedule. As she gets onto the highw

viktelen [127]

Complete Question

Alberta is going to have dinner at her grandmother's house, but she is running a bit behind schedule. As she gets onto the highway, she knows that she must exit the highway within 55 min if she is not going to arrive late. Her exit is 43 mi away. How much time would it take at the posted 60 mph speed?

Answer:

The time it would take at the given speed is $x = 43.00 \ minutes$