Answer:
Why ? Because 1 molecule of H2SO4 gives 2 H+ ions per molecule while only one H+ ion is required to neutralize 1 molecule of KOH. So, 1 molecule of H2SO4 can neutralize 2 molecules of KOH. Hence, we would require 525 ml of 0.03 M H2SO4 to neutralize 525 ml of 0.06 M KOH. How will we prepare 525 ml of 0.03 M H2SO4 ?
Explanation:
Now, we have 0.025 M H2SO4 and we do not know how much volume we have.
We will use the standard N1 X V1 = N2 X V2 for this calculation.
N1=0.025 M; V1=unknown; N2=0.03 M and V2=525 ml.
So V1= (0.03 X 525)/(0.025) = 630 ml.
Answer:
(CH2)3CH3 > CH2CH2CH3 > CH2CH3 > CH3
Explanation:
Giving the following ; CH3, CH2CH3, CH2CH2CH3, (CH2)3CH3
Priority increases as the number of CH2 group increases and vice versa, as such the one with more CH2 group will be the highest priority and the least compound with the small CH2 group attached, will have the smallest priority.
The arrangement is as follows ; (CH2)3CH3 > CH2CH2CH3 > CH2CH3 > CH3
Ethane consists of 6C−H bonds and 1C−C bond. Total number of bonds is 7. Each bond is made up of two electrons
<h2>
<em>#</em><em>L</em><em>E</em><em>T</em><em>S</em><em> </em><em>STUDY</em></h2>
<em>#</em><em>B</em><em>R</em><em>A</em><em>I</em><em>N</em><em>L</em><em>E</em><em>S</em><em>T</em><em> </em><em>LOVE❣️</em>
Answer:
People can introduce their own biases into an experiment.
Explanation:
The amount of kinetic energu has depens upon an object's speed and its mass.
So its I and IV.
The correct answer is B.
Hope it helps!
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