Answer:
To calculate the percent composition, we need to know the masses of C, H, and O in a known mass of C9H8O4. It is convenient to consider 1 mol of C9H8O4 and use its molar mass (180.159 g/mole, determined from the chemical formula) to calculate the percentages of each of its elements:
%
C
9
mol C
×
molar mass C
molar mass
C
9
H
18
O
4
×
100
=
9
×
12.01
g/mol
180.159
g/mol
×
100
=
108.09
g/mol
180.159
g/mol
×
100
%
C
60.00
%
C
Answer:
92.4 grams.
Explanation:
- From the balanced reaction:
<em>CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O,</em>
1.0 mole of CaCO₃ reacts with 2.0 moles of HCl to produce 1.0 mole of CaCl₂, 1.0 mole of CO₂, and 1.0 mole of H₂O.
- We need to calculate the no. of moles of (104 g) of CaCO₃:
<em>no. of moles of CaCO₃ = mass/molar mass</em> = (104 g)/(100.08 g/mol) = <em>1.039 mol.</em>
<u><em>Using cross multiplication:</em></u>
1.0 mole of CaCO₃ produce → 1.0 mole of CaCl₂.
∴ 1.039 mole of CaCO₃ produce → 1.039 mole of CaCl₂.
∴ The amount of CaCl₂ produced = no. of moles x molar mass = (1.039 mol)(110.98 g/mol) = 114.3 g.
∵ percent yield of the reaction = [(actual yield)/(theoretical yield)] x 100.
Percent yield of the reaction = 80.15%, theoretical yield = 115.3 g.
<em>∴ actual yield = [(percent yield of the reaction)(theoretical yield)]/100 </em>= [(80.15%)/(115.3 g)] / 100 = <em>92.42 g ≅ 92.4 g.</em>
Answer:
No, the object with the smaller mass will have a greater change in motion.
Explanation:
Hope this helps!
2.07 M is the molarity of the final solution if 45.0 ml of 6.00M HCl is added to 130 ml of 
O.
Explanation:
Data given:
volume of HCl, V1 = 45 ml
molarity of the HCl solution, M1 = 6 M
final volume of the HCl solution after water is added, V2 = 130 ml
final molarity M2 =?
After the dilution, the molarity of the new solution can be found by using the formula:
M1V1 = M2V2
here M1 and V1 are the molarity and volume for concentrated solution, M2 and V2 represents the diluted solution's molarity and volume.
Applying the formula after rearranging the equation, we get
M2 = 
M2 = 
M2 = 2.07 M
The final molarity of the HCl solution is 2.07 M
Answer:
When potassium reacts with arsenic to form an ionic compound, each metal atom loses 1 electron(s) and each nonmetal atom gains 3 electron(s). There must be 3 potassium atom(s) for every 1 arsenic atom(s) in the reaction.
Explanation:
We need to consider the octet rule: each atom will gain or lose electrons to have 8 electrons in its valence shell.
- Potassium is in Group 1, so it has 1 valence electron, which will lose to form K⁺.
- Arsenic is in Group 15, so it has 5 valence electrons. Then, it will gain 3 electrons to form As³⁻.
To have an electrical molecule between K⁺ and As³⁻, we require 3 K⁺ and 1 As³⁻, and the resulting formula is K₃As.
