Answer:
2.2×10^8
Explanation:
Cu(OH)2(s)<---------> Cu^2+(aq) + 2OH^-(aq) Ksp=2.2 x 10 ^-20
2H3O^+(aq) + 2OH^-(aq) <-------> 4H2O(l). Kw= 1×10^14
Cu^2+(aq) + 4H2O(l) <--------> [Cu(H2O)4]^2+(aq)
Overall ionic reaction:
Cu(OH)2(s) +2H3O^+(aq) <---------> [Cu(H20)4]^2+(aq)
Equilibrium constant for the reaction: Ksp×Kw= 2.2 x 10 ^-20 × (1/(1×10^-14))^2
Keq= 2.2×10^8
Kw= ion dissociation constant of water
The answer is the principal quantum number
Hope this helps
Grinding as it’s a physical not chemical change :)
Answer:
- motors that run on electricity
- tires that improve gas mileage
Explanation:
The transportation is a major polluter of the air. The big problem with it is that it is necessary for the humans to be able to live and function properly, as the trade is happening through it, thus it is crucial for the economy. In order to stop or reduce the negative impact on the air quality, there are some solutions which can help. The motors that can run on electricity are an excellent method, as the production of electricity is not polluting the are as the fossil fuels are. The only problem is that this type of motors are still very expensive, so once their price is on pair with the combustion motors they can be used. Tires that are able to increase the efficiency of the transportation means can also be useful, as they will be able to reduce the amount of pollutants released into the atmosphere, because the transportation will use less fossil fuels for the same mileage.
Answer:
3.6 grams of NaCl are needed
Explanation:
Percent solution are solutions whose concentrations are expressed in percentages. The amount(either weight or volume) of a solute is expressed as a percentage of the total weight or volume of solution. Percent solutions can either be expressed as weight/volume % (wt/vol % or w/v %), weight/weight % (wt/wt % or w/w %), or volume/volume % (vol/vol % or v/v %).
A 6.0% wt/wt % solution contains 6 g of solute in 100 g of solution
Therefore, a 100 g solution contains 6.0 g of solute.
60 g of 6.0% solution will contain 60 g solution * 6.0 g solute/ 100 g solution
Mass of NaCl present = 3.6 g of NaCl
