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4 years ago

How can you tell when a solution is formed?

2 answers:

5 0

You may tell when a solution os formed when the item or particle, such as sugar or salt,
dissolves completely in the solvent, such as water.

Basically, you know when a solution is formed when the material you have placed in the solvent disappears :P

svet-max [94.6K]4 years ago

4 0

When the solute is completely dissolved into the solvent.

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Is C3N2H4 a organic compound

KengaRu [80]

Organic compounds and inorganic compounds form the basis of chemistry. ... Also, nearly all organic compounds contain carbon-hydrogen or C-H bonds. Note, containing carbon is not sufficient for a compound to be considered organic! Look for both carbon and hydrogen.Jun 1, 2018

8 0

3 years ago

Read 2 more answers

A gas held in a balloon at 5L has its temperature doubled. What will the new volume of the balloon be?

alexandr402 [8]

Answer:

2.5l

Explanation:

They higher the temprature the higher the volume

3 0

3 years ago

A chemist measures the amount of oxygen gas produced during an experiment. She finds that 276. g of oxygen gas is produced. Calc

Nuetrik [128]

<h2>Answer:</h2>

0.152 moles

<h3>Given that: </h3>

The mass of the oxygen gas produced = 4.87 g

Also, The molar mass of oxygen gas, = = 32 g/mol

The formula for the calculation of moles is shown below:

moles = $\frac{Mass-taken}{Molar-mass}$ <u>*</u>

Thus,

moles = $\frac{4.87g}{32g/mol }$

Both given values and the answer is in 3 significant digits.

brainlist pls?

*i put a dash between mass and taken as formulas do no spaces

6 0

3 years ago

the density of dry air at 20 degrees celsius is 1.20 g/L. What is the mass of air, in kilograms, of a room that measures 24.0m b

nika2105 [10]

Answer:

1728 kg is the mass of air for the room

Explanation:

An exercise of unit conversion.

The volume of the room will be:

24 m . 15 m . 4m = 1440 m³

Density of air is 1.20 g/L which means that in 1L, there is contained 1.20 g of air.

1L = 1dm³

1m³ = 1000 dm³

1440 m³ . 1000 = 1440000 dm³ ⇒ 1.44x10⁶ L

Density of air = 1.20 g/L = mass of air / volume of air

1.20 g/L = mass of air / 1.44x10⁶ L

1.20 g/L . 1.44x10⁶ L = mass of air → 1728000 grams

1 g = 1x10⁻³ kg

1728000 g / 1000 = 1728 kg

7 0

3 years ago

What is the formula for the precipitate when solutions of manganese (II) nitrate and

natita [175]

The precipitate formed when a solution of manganese(II) nitrate and

potassium sulfide react is Manganese sulfide (MnS)

To obtain the precipitate formed when a solution of manganese(II) nitrate and potassium sulfide react, we shall write the balanced ionic equation. This is illustrated below:

Manganese (II) nitrate => Mn(NO₃)₂

Potassium sulfide => K₂S

In solution, they will react as follow:

Mn(NO₃)₂ (aq) —> Mn²⁺(aq) + 2NO₃¯(aq)

K₂S(aq) —> 2K⁺(aq) + S²¯(aq)

Mn(NO₃)₂ (aq) + K₂S(aq) —>

Mn²⁺(aq) + 2NO₃¯(aq) + 2K⁺(aq) + S²¯(aq) —> MnS(s) + 2K⁺(aq) + 2NO₃¯(aq)

Cancel out the spectator ions (i.e K⁺ and NO₃¯)

Mn²⁺(aq) + S²¯(aq) —> MnS(s)

From the net ionic equation above, we can see that MnS is insoluble.

Therefore, the precipitate formed when a solution of manganese(II) nitrate and potassium sulfide react is Manganese sulfide (MnS)

Learn more: brainly.com/question/21280827

6 0

2 years ago