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3 years ago

21. A quantity of food would last a

Mathematics

2 answers:

dalvyx [7]3 years ago

7 0

Answer:

15 days

Step-by-step explanation:

5 x 21 = 105

105/7 = 15

dlinn [17]3 years ago

3 0

Answer:

15 days

Step-by-step explanation:

As the number of people in that family increases the time taken reduces, so the time is in inverse proportion to the number of people in that family.

Let the number of days taken by a family of 7 to finish a quantity of food be x.

⇒ $\frac{x}{21}$ = $\frac{1}{\frac{7}{5} }$

⇒ $\frac{x}{21}$ = $\frac{5}{7}$

⇒ x = $\frac{21 * 5}{7}$

x = 15

∴ It would take a family of 7 15 days to finish a quantity of food.

Hope this helps!!!

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At a college, 71% of courses have final exams and 45% of courses require research papers. Suppose that 26% of courses have a res

Degger [83]

Answer:

.9 or 90%

.1 or 10%

Step-by-step explanation:

E= Exam

P=Paper

E= .71

P= .45

E∩P=.26

A.) E∪P=?

E∪P= E+P-E∩P

.71+.45-.26= .9

B.) E'∩P' = (E∪P)'

(E∪P)' = 1-.9 = .1

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2 years ago

Simplify. 3^2+ (9-8/2)

solmaris [256]

Hi there! Hopefully this helps!

-----------------------------------------------------------------------------------------------------------

Answer: 14.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

First we calculate 3 to the power of 2 and get 9.

9 + 9 - $\frac{8}{2}$ = 14.

Now we add 9 + 9 to get 18.

18 - $\frac{8}{2}$ = 14.

Then, we divide 8 by 2 to get 4.

18 - 4 = 14.

Then we subtract 4 from 18 to get.....You guessed it, 14!

3 0

3 years ago

Read 2 more answers

Point O is between points Mand N on line segment MN. O is the midpoint of line segment MN if

s2008m [1.1K]

Diagram:
M------------O-------------N
................. ^ midpoint
Obviously if O is the *mid*point, then it is exactly halfway between M and N. That also means it has bisected the segment into two equal parts.
On one side you have MO (or OM, if you like)
On the other side you have ON.
In order for O to be the midpoint:
ON = OM

8 0

2 years ago

Circle P is described by the equation (x−1)2+(y+6)2=9 and circle Q is described by the equation (x+4)2+(y+14)2=4. Select from th

xeze [42]

Answer:

(a) Circle Q is 9.4 units to the center of circle P

(b) Circle Q has a smaller radius

Step-by-step explanation:

Given

$P:(x - 1)^2 + (y + 6)^2 = 9$

$Q:(x + 4)^2 + (y + 14)^2 = 4$

Solving (a): The distance between both

The equation of a circle is:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$Center: (h,k)$

$Radius:r$

P and Q can be rewritten as:

$P:(x - 1)^2 + (y + 6)^2 = 3^2$

$Q:(x + 4)^2 + (y + 14)^2 = 2^2$

So, for P:

$Center = (1,-6)$

$r = 3$

For Q:

$Center = (-4,-14)$

$r = 2$

The distance between them is:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

Where:

$Center = (1,-6)$ --- $(x_1,y_1)$

$Center = (-4,-14)$ --- $(x_2,y_2)$

So:

$d = \sqrt{(1 - -4)^2 + (-6 - -14)^2$

$d = \sqrt{(5)^2 + (8)^2$

$d = \sqrt{25 + 64$

$d = \sqrt{89$

$d = 9.4$

Solving (b): The radius;

In (a), we have:

$r = 3$ --- circle P

$r = 2$ --- circle Q

By comparison

$2 < 3$

Hence, circle Q has a smaller radius

4 0

3 years ago

Mai solved the equation incorrectly. Identify and explain Mai’s error.

Ivanshal [37]

YOU CANNOT ADD OR SUBTRACT FRACTIONS WITH DIFFERENT DENOMINATORS!! You need to find the LCD (Lowest Common Denominator) for 6 and 2 with is 6!!
(CORRECTED WORK SHOWN BELOW)

8 0

2 years ago