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Sati [7]
3 years ago
5

Why does a Parallel Circuit still continue to function after a switch turns off one bulb but continues to pass through the secon

d bulb? (please be as specific as possible)​
Physics
1 answer:
sertanlavr [38]3 years ago
6 0

Explanation:

In short, when we switch off a branch, the remaining branch still forms a complete circuit with the battery, so electricity still pass through the remaining branch.

Technically speaking, the voltage in each branch is the same, and the resistance of the light bulb remains unchanged (neglect effect of temp.) by V=IR, the current should remain unchanged after switching off the other branch.

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Help me with this question.
san4es73 [151]

Answer:

<em>huh? sorry i can</em><em>'</em><em>t read perfectly:((</em>

7 0
3 years ago
A deep space probe travels in a straight line at a constant speed of over 16,000 m/s. Assuming there is no friction in space, if
77julia77 [94]
C because when the part gets out of the probe it would no longer stay contacted
6 0
3 years ago
A long string is wrapped around a 6.6-cm-diameter cylinder, initially at rest, that is free to rotate on an axle. The string is
lys-0071 [83]

Answer:

\omega_f=571.42\ rpm

Explanation:

It is given that,

Diameter of cylinder, d = 6.6 cm

Radius of cylinder, r = 3.3 cm = 0.033 m

Acceleration of the string, a=1.5\ m/s^2

Displacement, d = 1.3 m

The angular acceleration is given by :

\alpha =\dfrac{a}{r}

\alpha =\dfrac{1.5}{0.033}

\alpha =45.46\ rad/s^2

The angular displacement is given by :

\theta=\dfrac{d}{r}

\theta=\dfrac{1.3}{0.033}

\theta=39.39\ rad

Using the third equation of rotational kinematics as :

\omega_f^2-\omega_i^2=2\alpha \theta

Here, \omega_i=0

\omega_f=\sqrt{2\alpha \theta}

\omega_f=\sqrt{2\times 45.46\times 39.39}

\omega_f=59.84\ rad/s

Since, 1 rad/s = 9.54 rpm

So,

\omega_f=571.42\ rpm

So, the angular speed of the cylinder is 571.42 rpm. Hence, this is the required solution.

5 0
4 years ago
Rama's weight is 4okg: She is carrying a load of 20kg up to a height of 20 meters.what work does she do?Also mention its type of
Maslowich

Answer:

rama is doing

Explanation:

work done=f×d×g

=60×20×9.8

=11760j

she is doing work against gravity

mark me

8 0
3 years ago
When a neutrally charged atom loses an electron to another atom, the result is the creation of
Ostrovityanka [42]
That would make a cation. If it gained one instead, then it would make an anion.
5 0
3 years ago
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