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3 years ago

11

Round the number 14.587020 to 4 significant digits.

2 answers:

crimeas [40]3 years ago

6 0

correct answer is a because that was the coreect answer on e2020

PilotLPTM [1.2K]3 years ago

4 0

A. 14.59 is correctly rounded to 4 significant digits.

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In a standing wave, areas of destructive interference are the?

pentagon [3]

Answer: B. Nodes

Explanation:

Standing waves (so called because they seem to be immobile) occur when two waves interfere with the same frequency, amplitude but with different direction, along a line with a phase difference of half wavelength.

In these waves there are two types of points:

The <u>nodes</u>, which are points that remain motionless or stationary and do not vibrate. They are <u>due to the destructive interference of both waves when they meet. </u>

The antinodes, which are points that vibrate with a maximum vibration amplitude. They are <u>due to the non-destructive interference of both waves</u>.

8 0

3 years ago

The mass of the earth is 5.96/10kg^24. The radius of the earth is approximately 6.37x10^6 calculate the force of gravity

n200080 [17]

<h2>Answer:g=9.79 $ms^{-2}$ ,A object of mass $m$ at the surface of earth experiences a force $mg$ </h2>

Explanation:

Let $M$ be the mass of earth.

Let $R$ be the radius of earth.

Let $G$ be the universal gravitational constant.

Given,

$M=5.96\times 10^{24}Kg$

$R=6.37\times 10^{6}m$

$G=6.67259 \times 10^{-11}$ $Nm^{2}Kg^{-2}$

Let $g$ be the acceleration due to gravity.

Then, $g=\dfrac{GM}{R^{2}}$

$g=\frac{6.67259 \times 10^{-11}\times 5.96\times 10^{24}}{(6.37\times 10^{6})^{2}}$

$g=9.79ms^{-2}$

A object of mass $m$ at the surface of earth experiences a force $mg$

3 0

3 years ago

Which refers to the amount of heat required to change the temperature of 1 gram of a substance by 1°C and is related to the chem

timama [110]

Answer:

Specific heat

Explanation:

8 0

3 years ago

What type of ion is formed by a non-metal atom?

Verizon [17]

Non metals produce something called protons they are ions

7 0

3 years ago

Amazon rectangular bar of low carbon steel A-36 is exposed to an axial strees of 150 MPa. What is the original length of the bar

kolbaska11 [484]

Answer:

1.8m

Explanation:

Let the Elastics of the steel ASTM-36 $E = 200000 MPa$

The strain of the bar when subjected to 150 MPa is

$\epsilon = \frac{\sigma}{E} = \frac{150}{200000} = 0.00075$

Therefore, if the bar elongates by 1.35 mm, then the original length L would be:

$\epsilon = \frac{\Delta L}{L}$

$L = \frac{\Delta L}{\epsilon} = \frac{1.35}{0.00075} = 1800 mm$ or 1.8m

5 0

3 years ago