the answer is spiral galaxies
Answer:
At the earth's surface g = G M / R^2 where G is the gravitational constant
at H g1 = G M / (R + H)^2 using Gauss' theorem for enclosed mass
g1 = G M / (R^2 + 2 R H) ignoring H^2 as it is small compared to R^2
g / g1 = (R^2 + 2 R H) / R^2 = 1 + 2 R H
g = g1 + 2 R H g1
g1 - g = - 2 R H or H = (g1 - g) / 2 R
Answer:
C
Explanation:
Since the circuit is in parallel there will be no effect on the other loads.
Answer:
5080.86m
Explanation:
We will divide the problem in parts 1 and 2, and write the equation of accelerated motion with those numbers, taking the upwards direction as positive. For the first part, we have:
We must consider that it's launched from the ground () and from rest (), with an upwards acceleration that lasts a time t=9.7s.
We calculate then the height achieved in part 1:
And the velocity achieved in part 1:
We do the same for part 2, but now we must consider that the initial height is the one achieved in part 1 () and its initial velocity is the one achieved in part 1 (), now in free fall, which means with a downwards acceleration . For the data we have it's faster to use the formula , where d will be the displacement, or difference between maximum height and starting height of part 2, and the final velocity at maximum height we know must be 0m/s, so we have:
Then, to get , we do:
And we substitute the values:
Answer: The force will exert into the tree causing it to absorb the compact hit by the car which means the car gets damaged severely but the tree maybe only has a tiny crack. Mark me as Brainliest! :)
Explanation: