1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
antoniya [11.8K]
3 years ago
13

How much work is accomplished when a force of 300N pushes a box across the floor for a distance of 100 meters?

Physics
2 answers:
Nesterboy [21]3 years ago
5 0

So the correct ans is B.

hope it helps u.

Wewaii [24]3 years ago
4 0

Answer:

D.30000 J

Explanation:

Work done = force x distance

From the question

Force F = 300N

Distance d = 100m

Therefore using the above formula, we have

W.d = 300N x 100m

= 30000 J

Work done is measured in Joules J

You might be interested in
A quartz crystal vibrates with a frequency of 93621 Hz. What is the period of the crystals motion? T=1/93621 does not give me th
hram777 [196]

Answer:0.0000107s

Explanation:

f=1/T

T=1/f

f=93621 1/s

t=1/93621

T=0.00001068  s

3 0
3 years ago
A 115 g hockey puck sent sliding over ice is stopped in 15.1 m by the frictional force on it from the ice.
Hoochie [10]

Answer:

(a) Ff = 0.128 N

(b μk = 0.1135

Explanation:

kinematic analysis

Because the hockey puck  moves with uniformly accelerated movement we apply the following formulas:

vf=v₀+a*t Formula (1)

d= v₀t+ (1/2)*a*t² Formula (2)

Where:  

d:displacement in meters (m)  

t : time in seconds (s)

v₀: initial speed in m/s  

vf: final speed in m/s  

a: acceleration in m/s

Calculation of the acceleration of the  hockey puck

We apply the Formula (1)

vf=v₀+a*t      v₀=5.8 m/s ,  vf=0

0=5.8+a*t

-5.8 = a*t

a= -5.8/t   Equation (1)

We replace a= -5.8/t in the Formula (2)

d= v₀*t+ (1/2)*a*t²   ,  d=15.1 m ,  v₀=5.8 m/s

15.1 = 5.8*t+ (1/2)*(-5.8/t)*t²  

15.1= 5.8*t-2.9*t

15.1= 2.9*t

t = 15.1 / 2.9

t= 5.2 s

We replace t= 5.2 s in the equation (1)

a= -5.8/5.2

a= -1.115 m/s²

(a) Calculation of the  frictional force (Ff)

We apply Newton's second law

∑F = m*a    Formula (3)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Look at the free body diagram of the  hockey puck in the attached graphic

∑Fx = m*a     m= 115g * 10⁻³ Kg/g = 0.115g    ,  a= -1.12 m/s²

-Ff = 0.115*(-1.115)  We multiply by (-1 ) on both sides of the equation

Ff = 0.128 N

(b) Calculation of the coefficient of friction (μk)

N: Normal Force (N)

W=m*g= 0.115*9.8= 1.127 N : hockey puck  Weight

g: acceleration due to gravity =9.8 m/s²

∑Fy = 0

N-W=0

N = W

N =  1.127 N

μk = Ff/N

μk = 0.128/1.127

μk = 0.1135

8 0
3 years ago
Which statement correctly describes the gravitational potential energy of the pendulum based on this diagram?
MrRa [10]
I think it's 'C' but I won't know for sure until you let me see the diagram.
8 0
3 years ago
A gas in a cylinder expands from a volume of 0.110 m³ to 0.320 m³. heat flows into the gas just rapidly enough to keep the press
Elden [556K]

80000 Joule is the change in the internal energy of the gas.

<h3>In Thermodynamics, work done by the gas during expansion at constant pressure:</h3>

ΔW = -pdV

ΔW = -pd (V₂ -V₁)

ΔW = - 1.65×10⁵ pa (0.320m³ - 0.110m³)

     = - 0.35×10⁵ pa.m³

     = - 35000 (N/m³)(m³)

     = -35000 Nm

ΔW = -35000 Joule

Therefore, work done by the system = -35000 Joule

<h3>Change in the internal energy of the gas,</h3>

ΔV = ΔQ + ΔW

Given:

ΔQ = 1.15×10⁵ Joule

ΔW = -35000 Joule

ΔU = 1.15×10⁵ Joule - 35000 Joule

      = 80000 Joule.

Therefore, the change in the internal energy of the gas= 80000 Joule.

Learn more about thermodynamics here:

brainly.com/question/14265296

#SPJ4

3 0
2 years ago
Which team sport has individual competition but ultimately working together to win the contest?
sashaice [31]
Sports like swimming and track are individual races but in the end everyone on the team races come together to make a team placement.
7 0
3 years ago
Other questions:
  • What is the total amount of heat in a substance
    12·1 answer
  • Meteoroid is the term used to describe a solid particle that
    6·1 answer
  • A ball traveling at a speed ν0 rolls off a desk and lands at a horizontal distance x0 away from the desk, as shown in the figure
    7·1 answer
  • What are the names of the 2 charged particles in an atom and what are their charges
    10·1 answer
  • Physics Help Please:
    12·2 answers
  • With what minimum speed must you toss a 130 g ball straight up to just touch the 14-m-high roof of the gymnasium if you release
    13·1 answer
  • 1.) How much potential energy does an object with a mass of 3 kg have on top of a stand 12 meters
    13·1 answer
  • Let the displacement function of a particle is x(t)=(20t^2-15t+200). Find the total displacement, instantaneous velocity and ins
    7·1 answer
  • How much force would you need to accelerate a 4 kg object from a standstill to 5 m/s2?
    5·1 answer
  • How long does 100m long train take a cross a bridge of length 4.9 km at a speed of 50m/s
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!