Answer:
(1) Bromination, (2) E2 elimination and (3) epoxidation
Explanation:
- In the first step, -OH group in cyclopentanol is replaced by more facile leaving group Br by treating cyclopentanol with

- In the second step, E2 elimination in presence of strong base e.g. NaOEt/EtOH produce cyclopentene
- In the third step, treatment of cyclopentene with mCPBA produces 1,2-epoxycyclopentane
- Full reaction scheme has been shown below
Answer:
200 g
Explanation:
Stainless steel is an alloy of iron, chromium, nickel, and manganese metals. A 2.000 g sample contains 10.0% nickel (mass percent), that is, there are 10.0 g of nickel every 100 g of the sample. The mass of nickel in the sample is:
2.000 g sample × (10.0 g Nickel/100 g sample) = 200 g Nickel
There are 200 grams of Nickel in the 2.000 g-sample.
Let's begin with the basic values that will be used in the solution.
The formula of propane is C3H8. It is an alkane, a hydrocarbon with the general formula of CnH2n+2. Notice that hydrocarbons have only Carbon and Hydrogen atoms. Its molar mass (M) is 44 g.
Molar Mass Calculation is done as like that
C=12 g/mol, H=1 g/mol. 1 mole propane has 3 moles Carbon atoms and 8 mole Hydrogen atoms. M(C3H8)= 3*12+ 8*1= 44 g
Combustion reaction of hydrocarbons gives carbon dioxide and water by releasing energy. That energy is called as enthalpy of combustion (ΔHc°).
ΔHc° of propane equals -2202.0 kj/mol. Burning of 1 mole C3H8 releases 2202 kj energy. Minus sign only indicates that the energy is given out ( an exothermic reaction ).
Let's write the combustion reaction.
C3H8 + O2 ---> CO2 + H20 (unbalanced) ΔHc° = -2202 kj/mol
Now, we calculate mole of 20 kg propane. Convert kilogram into gram since we use molar mass is defined in grams.
mole=mass/molar mass ; n=m/M ; n= 20000 g /44 (g/mol)=454 mole
1 mole propane releases 2202 kj energy.
454 mole propane release 2202 kj *454= 1000909 kj
The answer is 1000909 kj.
Kind of this is probably wrong Mass weight of solid, volume weight of liquid?
<u>Answer:</u> The law that related the ideal gas law is 
<u>Explanation:</u>
There are 4 laws of gases:
- <u>Boyle's Law:</u> This law states that pressure is inversely proportional to the volume of the gas at constant temperature.
Mathematically,

- <u>Charles' Law:</u> This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,

- <u>Gay-Lussac Law:</u> This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,

- <u>Avogadro's Law:</u> This law states that volume is directly proportional to number of moles at constant temperature and pressure.
Mathematically,

Hence, the law that related the ideal gas law is 