Answer:
1)
(500.mL)(.200M)/.150M = 667 mL
667mL - 500mL = 167mL of water is needed
2)
1.0 L = 1000mL
M1 V1 = M2 V2
(1.6 mol/L) (175 mL) = (x)(1000mL)
x = .28M
During normal respiration, about 500ml of air enters and leaves the lungs with each respiratory cycle. This is called the<u> tidal volume</u>.
When a person is relaxed, the normal amount of air such a person breathes in and out is called the tidal volume. It is usually measured in millimeters. For the average adult male, it is 500ml, and the tidal volume of average adult female 400ml.
In order to regulate oxygen intake and expulsion of carbon dioxide, the lungs act as buffers in order to absorb the maximum amount of oxygen possible for respiration and other metabolic functions in the body.
When the tidal volume is above or below the 500ml mark, it could signal the presence of underlying pathological conditions like bronchitis, emphysema and asthma.
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Answer:
3.75 L
Explanation:
We can solve this problem by using <em>Charles' law</em>, which states:
Where subscript 1 stands for initial volume and temperature and subscript 2 for final volume and temperature, meaning that in this case:
We <u>input the data</u>:
- 2.5 L * 300 K = V₂ * 200 K
And <u>solve for V₂</u>:
Answer:
no it is a ionic compound
Explanation:
ᗯᕼᗩT ᑕOᑎᑕᗴᑭT ᗩᖇᗴ ᑌ TᗩᑭKIᑎᘜ ᗩᗷOᑌT......
