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3 years ago

Ok, so i have 506k and I now have 327k. What is the rate of decrease in percent? I'll mark Brainliest!!!

Mathematics

2 answers:

Margaret [11]3 years ago

5 0

Attached below in the image. There is a 35% decrease.

KiRa [710]3 years ago

3 0

Answer:

= 35.3755% decrease

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Please help me due tmm second question

AURORKA [14]

Not sure if the math is correct but I think that it is $199.5

6 0

4 years ago

A telephone pole has a wire attached to its top that is anchored to the ground. the distance from the bottom of the pole to the

kirza4 [7]

The height of the pole is 96 feet

In mathematics, the Pythagorean theorem, or Pythagoras' theorem, is a fundamental relation in Euclidean geometry among the three sides of a right triangle. It states that the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares on the other two sides. This theorem can be written as an equation relating the lengths of the legs a, b and the hypotenuse c, often called the Pythagorean equation:[1]

$a^{2}+b^{2}=c^{2},$

Create a diagram of the scenario first. You would have a right triangle with a hypotenuse (longest side) of h + 4, a longest leg of h - 68, and one leg of length h to represent the pole.

Set up the equation $h^2 + (h - 68)^2 = (h + 4)^2$ using the Pythagorean theorem ( $a^2 + b^2 = c^2$ ).

$h^2 + (h - 68)^2 = (h + 4)^2$

On simplifying we get

$h^2+h^2-136h+4624 = h^2+8h+16$

$2h^2-136h+4624=h^2+8h+16$

$h^2-144h+4608=0$

Solving using quadratic formula

$h_{1,\:2}=\frac{-\left(-144\right)\pm \sqrt{\left(-144\right)^2-4\cdot \:1\cdot \:4608}}{2\cdot \:1}$

$h_1=\frac{-\left(-144\right)+48}{2\cdot \:1},\:h_2=\frac{-\left(-144\right)-48}{2\cdot \:1}$

h1 = 96 feet , h2 = 48 feet

If height would have been 48 feet then the other side would have a negative value as as 48 - 68 = -20 .

Hence the height of the pole is 96 feet

Learn more about Pythagoras theorem here :

brainly.com/question/343682

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7 0

2 years ago

Find the domain and the range of the relation shown on the

irinina [24]

The domain of a graph is the possible values of x, the graph can take.

(b) The domain of the relation is the interval [-10,10]

From the attached graph, we have the following observations on the x-axis.

The value of x starts from -10
The value of x ends at 10

So, the domain of x is from -10 to 10

Using interval notation, the domain of the relation is: $[-10,10]$

Ok, so i have 506k and I now have 327k. What is the rate of decrease in percent? I'll mark Brainliest!!!​

Ok, so i have 506k and I now have 327k. What is the rate of decrease in percent? I'll mark Brainliest!!!