Answer:
The answer is most likely A. Definite proportions
Explanation:
The Law of Definite proportions states that a given chemical compound always contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation.
Answer:

Explanation:
We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.
M_r: 32 60
CH₃OH + CO ⟶ CH₃COOH
m/g: 160
(a) Moles of CH₃OH

(b) Moles of CH₃COOH

(c) Mass of CH₃COOH

Answer:
Here's what I find
Explanation:
Heisenberg observed that if we want to locate a moving electron, we must bounce photons off it.
However, this makes it recoil. By the time the photon returns to our eye, the electron will no longer be in the same place.
He concluded that there is a limit to the precision with which we can simultaneously measure the position and speed (momentum) of a particle.
The more precisely we know the electron's speed, the less precisely we know its position and vice versa.
The uncertainty in the product of the two values cannot be less than a fixed small number.
<span><span>When you write down the electronic configuration of bromine and sodium, you get this
Na:
Br: </span></span>
<span><span />So here we the know the valence electrons for each;</span>
<span><span>Na: (2e)
Br: (7e, you don't count for the d orbitals)
Then, once you know this, you can deduce how many bonds each can do and you discover that bromine can do one bond since he has one electron missing in his p orbital, but that weirdly, since the s orbital of sodium is full and thus, should not make any bond.
However, it is possible for sodium to come in an excited state in wich he will have sent one of its electrons on an higher shell to have this valence configuration:</span></span>
<span><span /></span><span><span>
</span>where here now it has two lonely valence electrons, one on the s and the other on the p, so that it can do a total of two bonds.</span><span>That's why bromine and sodium can form </span>
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