Hi,
The force that acts on hydraulic machine is heavy therefore the content must be something that cannot be compressed by that kind of force, the gas can easily be compressed while a liquid is nearly impossible to.
For Anya:v 1 = 3.3 mph, v 2 = 8.3 mph5 : 2 = 2.5 mi ( half of the distance )
t1= d/v1 = 2.5 mi/ 3.3 mph = 0.7576 ht2 = d/v2 = 2.5 mi/8.3 mph = 0.3 hIn total: 0.7576 + 0.3 = 1.0576 hFor Ilya: 8.3 t / 2 + 3.3 t / 2 = 5 / * 28.3 t + 3.3 t = 1011.6 t = 10t = 10 : 11.6t = 0.86 hHe covers the distance for 0.86 h.His average speed:v = 5/0.86 = 5.81 mph.
Answer:
Please find the answer in the explanation.
Explanation:
When you try to move the magnet back and forth between the two coils, the motion of the magnet will be oscillatory and this action will cause current and EMF to induce
According to law of Faraday, current or EMF will be induced when a magnet is moved in the presence of coils
If the magnet continues to move back and forth between the two coils, what might be causing this will be the presence of the induced electromagnetic force between the two coils.
Answer:
The moon also falls towards the Earth, but having a tangential speed, the acceleration it has is used in the change of direction of its speed,
Explanation:
Newton explained that all objects attract each other, as the Earth is much greater than the apple, it is this that falls towards the Earth.
The moon also falls towards the Earth, but having a tangential speed, the acceleration it has is used in the change of direction of its speed, in general this acceleration is called centripetal
This principle is used in all circular motion devices, for example the merry-go-round in parks, the radius of the circle is proportional to the speed of the turn and therefore to the centripetal acceleration of the device.
Answer:
V0=27.4 m/s; t=0.8 s
Explanation:
Final position y=37.0 m, time = 2.3 s; Initial position is set to be zero. We calculate the initial speed with the kinematics equation:
We solve for initial speed
Now, using the same expression we estimated time to first reach 18.5 m :
Second order equation with solutions
t1=0.8 s and t2=4.8 s
The first time corresponds to the first reach.