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valkas [14]
3 years ago
13

You watch distant Sally Homemaker driving nails into a front porch at a regular rate of 1 stroke per second. You hear the sound

of the blows exactly synchronized with the blows you see. And then you hear one more blow after you see the hammering stop. Calculate the distance of Sally from you.
Physics
1 answer:
slamgirl [31]3 years ago
3 0

Answer:

343m

Explanation:

From the question Sally hits one blow every second

However, the sound is delayed by that same amount of time (1 sec)

If the speed of sound is 343m/s

Speed = Distance/Time

Speed = 343m/s

Time = 1s

Distance = Speed x Time

= 343 x 1 = 343m

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A baseball has a momentum of 6.0 kg m/s south and a mass of 0.15 kg. What is the baseball’s velocity? Show work
kupik [55]

Momentum of an object is defined as product of mass and velocity

so it is given as

P = m* v

here it is given that

mass = 0.15 kg

momentum = 6 kg m/s

so by plug in values in the above equation

6 = 0.15 * v

v = \frac{6}{0.15}

v = 40 m/s

so its speed will be 40 m/s

6 0
3 years ago
Why is it that I feel alone
lesya [120]

Answer: quarantine

Explanation:

5 0
3 years ago
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A cable weighing 0.6 pounds per foot is attached to a small 70-pound robot, and then the robot is lowered into a 50-foot deep we
Sav [38]

Answer:

4600 ft.Ibs

Explanation:

Work done by the robot in climbing to the top of the well = work done in carrying the cable and itself + work done in carrying about average half the mass of the cable attached to the robot

Now work done = Force × distance = (( 70 +7 ) × 50 ft) + (( 0.6 × 50 ft) × 25 ) = 3850 + 750 = 4600 ft.Ibs

8 0
4 years ago
An aquarium open at the top has 30-cm-deep water in it. You shine a laser pointer into the top opening so it is incident on the
Setler [38]

Answer:

You must add 8cm of water to the tank

Explanation:

In order to find how much the height is we will use the Snell Refraction law

.

This law relates the index of refraction of the water (n2), the index of refraction of the air (n1), the incidence angle relative to the vertical (theta1) and the refraction angle relative to the vertical (theta2) by using the next equation:

(n1)*(sin(theta1))=(n2)*(sin(theta2))

Then we will find the refraction angle relative to the vertical this way:

(n1/n2)*(sin(theta1))=sin(theta2)

(1/1.33)*(sin(45))=sin(theta2)

Then, theta2=32.12°

Now that we have this information we can imagine a triangle with a 30cm height and a 32.12° angle. This way we can find how much X is, this X will be the distance between the vertical line and the spot the beam hits the bottom, so we can use some trigonometry to find it, this way:

tan(32.12)=(X/30cm)

X=(tan(32.12))*(30cm)

Then, X=18.8cm, we can approximate it to 19cm

Once we have X we will add 5cm to it which is how much the beam needs to be moved, then the new X will be 24cm

Now, with the new horizontal distance we will find the new vertical distance, let´s call it Y, this way we will know how much water we must add to move the beam, then we will have a triangle with a vertical distance called Y, the same 32.12° angle will be used as we are still working with the air-water interface and a 19cm horizontal distance, then:

tan(32.12)=(24cm/Y)

Y=(24cm/tan(32.12))

Then, Y=38cm

In this case, you must add 8cm of water to the tank to move the beam on the bottom 5cm

5 0
3 years ago
Un ladrón viaja en un auto a una velocidad excesiva de 30m/s, en dicho momento un policía de tránsito, lo observa y monta en su
tester [92]

Answer:

t = 12 s

Explanation:

To find the time in which the police reaches the thief you write the equation of motion of both thief and police:

The thief has a constant velocity, the position is then given by:

x=vt     (1)

The police has an acceleration, then the position is:

x=v_ot+\frac{1}{2}at^2   (2)

the time in which the police reaches the thief is when their positions are equal, that is, when expression (1) equals expression (2). But before you calculate the acceleration of the police:

a=\frac{v-v_o}{t}\\\\v_o=0m/s\\\\a=\frac{50m/s}{10s}=5\frac{m}{s^2}

you replace this values in (2) and you equal the expression (1) and (2) (with vo = 0):

vt=\frac{1}{2}at^2\\\\\frac{1}{2}at^2-vt=0\\\\(\frac{1}{2}at-v)t=0

one root is t = 0s, but it is omitted because is the momment in which the thief pass in front of the police. The other root is:

\frac{1}{2}at-v=0\\\\t=\frac{2v}{a}=\frac{(2)(30m/s)}{5m/s^2}=12s

hence, the time is 12 s

8 0
3 years ago
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