Answer:
See below
Explanation:Plot the known concentrations and adsorbance data. Draw a best fit line through thwe points. When the absorbance of a solution of unknown concentration (but same substance) is determined, find the concentration from the line at that absorption value. See attached graph.
E.g., an sample of the same substance had an absorbance of 0.35. Find that on the x scale and then determine the concentration that would be required to produce that level of absorbance. 0.483M in this case.
Anode- oxidization
Cathode-reduction
An example of a heterogeneous catalyst is a catalytic converter. A catalytic converter is an emissions control device that converts toxic pollutants in exhaust gas to less toxic pollutants by catalyzing a redox reaction (oxydation or reduction).
Structure along with ¹H-NMR is shown below.
Signal for Hₐ; Based on multiplicity of of the peak, a
Singlet peak (the only singlet peak present in spectrum) at
2.2 ppm was assigned to Hₐ. As the methyl group in not coupling with any other proton so it gave a singlet peak.
Signal for Hb; Based on multiplicity of of the peak, a
Quartet peak (the only quartet peak present in spectrum) at
2.4 ppm was assigned to Hb. As the methylene group in coupling with methyl group having three protons so it gave a Quartet peak.
Signal for Hc; Based on multiplicity of of the peak, a
Triplet peak (the only triplet peak present in spectrum) at
1.1 ppm was assigned to Hc. As the methyle group in coupling with methylene group having two protons so it gave a Triplet peak.
Answer: -345.2 KJ
Explanation: As we know that ,dG=dH-TdS
T=25+273=298 K
dG= -356 x1000-298(-36)= -356000+10728
=-345272 j
= -345.2 KJ