Four binary ionic compounds that could be formed from each of these ions are;
- Zn^2+ - ZnCl2, ZnI2, ZnBr2, ZnF2
- Pb^4+ - PbF4, PbCl4, PbBr4, PbI4
- Br^- - MgBr2, NaBr, CaBr2, KBr
- S^2- - CaS, MgS, Na2S, K2S
<h3>What are binary ionic compounds?</h3>
Binary ionic compounds are those compounds that contain only two elements. The ionic compounds are those compounds that contain ions. The compounds are able to dissolve in water and they have high melting and boiling points.
Now, four binary ionic compounds that could be formed from each of these ions are;
- Zn^2+ - ZnCl2, ZnI2, ZnBr2, ZnF2
- Pb^4+ - PbF4, PbCl4, PbBr4, PbI4
- Br^- - MgBr2, NaBr, CaBr2, KBr
- S^2- - CaS, MgS, Na2S, K2S
Learn more about ionic compounds:brainly.com/question/9167977?
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Answer:
The hydroxide [OH-] concentration of the solution is 1.26*10⁻⁵ M.
Explanation:
The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution.
POH indicates the concentration of hydroxyl ions [OH-] present in a solution and is defined as the negative logarithm of the activity of hydroxide ions (that is, the concentration of OH- ions):
pOH= -log [OH-]
A solution has a pOH of 4.90. Replacing in the definition of pOH:
4.90= -log [OH-]
Solving:
-4.90= log [OH-]
1.26*10⁻⁵ M= [OH-]
<u><em>The hydroxide [OH-] concentration of the solution is 1.26*10⁻⁵ M.</em></u>
im a container or a glass
Answer:
1.44L
Explanation:
P1V1/T1=P2V2/T2
since the temperature didn’t change, stay at 20celsius, we can ignore T1 and T2.T1=T2
(1.00atm)(3.60L)=(2.50 atm)V2
V2=(1.00atm)(3.60L)/(2.50atm)
=1.44L
