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3 years ago

I need help with that plz got it rong it’s not 4

Mathematics

2 answers:

QveST [7]3 years ago

5 0

3 because x is equal to 3

stepan [7]3 years ago

3 0

Answer:

Step-by-step explanation:

x = 3

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In a survey of music preferences 81 out of 450 students said that they preferred country music what percent of the students pref

Kazeer [188]

To write 81/450 as a percent have to remember that 1 equal 100% and that what you need to do is just to multiply the number by 100 and add at the end symbol % .

81/450 * 100 = 0.18 * 100 = 18% 
81/450 as a percent equals 18%

6 0

3 years ago

Find the area of a circle with radius, r = 6.43m. Give your answer rounded to 2 DP.

Vesna [10]

Answer:

129.89 m²

Step-by-step explanation:

Area of a circle of radius r is A = πr².

If r = 6.43 m, then A = π(6.43 m)² = 129.89 m²

5 0

3 years ago

I need help on a equation −4a5⋅6a5

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I don’t understand the equation but you can use Photomath to solve any equation you need to solve. It’s and app for free.

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3 years ago

A line passes through the points (–3, –4) and (6, 2). What number is the x-intercept?

LuckyWell [14K]

Answer:

Step-by-step explanation:

$\bold{METHOD\ 1}$

$\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{x-intercept:}\ (x,\ 0).\\\\\text{Susbtitute the coordinates of the points to the formula of a slope}\\\\(-3,\ -4),\ (6,\ 2),\ (x,\ 0):\\\\m=\dfrac{2-(-4)}{6-(-3)}=\dfrac{2+4}{6+3}=\dfrac{6}{9}=\dfrac{6:3}{9:3}=\dfrac{2}{3}\\\\m=\dfrac{0-2}{x-6}=\dfrac{-2}{x-6}\\\\\text{Therefore we have the equation:}\\\\\dfrac{-2}{x-6}=\dfrac{2}{3}\qquad\text{cross multiply}\\\\2(x-6)=(-2)(3)\\\\2(x-6)=-6\qquad\text{divide both sides by 2}\\\\x-6=-3\qquad\text{add 6 to both sides}\\\\x=3$

$\bold{METHOD\ 2}\\\\\text{Look at the picture.}$

Mark points in the coordinate system.

Lead a line through these points.

Read x-intercept.

5 0

3 years ago

Read 2 more answers

Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t

nataly862011 [7]

Let (x, y, z) be a point on the plane in the first octant. The box formed by this point has volume xyz, and you want to maximize this subject to the equation of the plane.

Use the method of Lagrange multipliers: the Lagrangian is

L(x, y, z) = xyz - λ (x + 2y + 3z - 6)

Find its critical points:

∂L/∂x = yz - λ = 0

∂L/∂y = xz - 2λ = 0

∂L/∂z = xy - 3λ = 0

∂L/∂λ = -(x + 2y + 3z - 6) = 0

Solving the first three equations for λ gives

λ = yz = xz/2 = xy/3

Solve these equations for y and z :

• yz = xz/2 => y = x/2 => 2y = x

• yz = xy/3 => z = x/3 => 3z = x

Substitute these solutions into the last equation and solve for x, then again for y and z :

x + 2y + 3z - 6 = 3x - 6 = 0 => 3x = 6 => x = 2, y = 1, z = 2/3

At this critical point, the maximum volume is

xyz = 2*1*2/3 = 4/3

4 0

3 years ago