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cricket20 [7]
2 years ago
5

Good Morning. Can you help me on this question please?

Engineering
2 answers:
AnnyKZ [126]2 years ago
8 0

Answer:

b

Explanation:

MatroZZZ [7]2 years ago
7 0

Answer:

The correct answer is C

Explanation:

because sound waves travel through solids fastest.

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wind vane if it can be used to show wind speed and the other is a

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AVH
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Answer: preventive maintenance

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2 years ago
For surface-mounted and pendant-hung luminaires, support rods should be placed so that they extend about ____
7nadin3 [17]

Answer:

One

For surface-mounted and pendant-hung luminaires, support rods should be placed so that they extend about _one___

<h3>what is supported mounted?</h3>
  • A structure that holds up or serves as a foundation for something else. Support is a synonym for mounting.

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4 0
1 year ago
If you are trying to land the plane, which part(s) would you move? How would you move it/them?
KiRa [710]

Answer: hope it helps

Explanation:Moving air has a force that will lift kites and balloons up and down. Air is a mixture ... Here is a simple computer simulation that you can use to explore how wings make lift. ... All these dimensions together combine to control the flight of the plane. A pilot ... When the rudder is turned to one side, the airplane moves left or right.

7 0
3 years ago
A two-dimensional flow field described by
Oduvanchick [21]

Answer:

the answer is

Explanation:

<h2>  We now focus on purely two-dimensional flows, in which the velocity takes the form </h2><h2>u(x, y, t) = u(x, y, t)i + v(x, y, t)j. (2.1) </h2><h2>With the velocity given by (2.1), the vorticity takes the form </h2><h2>ω = ∇ × u = </h2><h2> </h2><h2>∂v </h2><h2>∂x − </h2><h2>∂u </h2><h2>∂y </h2><h2>k. (2.2) </h2><h2>We assume throughout that the flow is irrotational, i.e. that ∇ × u ≡ 0 and hence </h2><h2>∂v </h2><h2>∂x − </h2><h2>∂u </h2><h2>∂y = 0. (2.3) </h2><h2>We have already shown in Section 1 that this condition implies the existence of a velocity </h2><h2>potential φ such that u ≡ ∇φ, that is </h2><h2>u = </h2><h2>∂φ </h2><h2>∂x, v = </h2><h2>∂φ </h2><h2>∂y . (2.4) </h2><h2>We also recall the definition of φ as </h2><h2>φ(x, y, t) = φ0(t) + Z x </h2><h2>0 </h2><h2>u · dx = φ0(t) + Z x </h2><h2>0 </h2><h2>(u dx + v dy), (2.5) </h2><h2>where the scalar function φ0(t) is arbitrary, and the value of φ(x, y, t) is independent </h2><h2>of the integration path chosen to join the origin 0 to the point x = (x, y). This fact is </h2><h2>even easier to establish when we restrict our attention to two dimensions. If we consider </h2><h2>two alternative paths, whose union forms a simple closed contour C in the (x, y)-plane, </h2><h2>Green’s Theorem implies that   </h2><h2> </h2><h2> </h2><h2> </h2><h2> </h2><h2> </h2><h2></h2><h2></h2>
5 0
3 years ago
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