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saw5 [17]
3 years ago
9

Before taking off a plane travels at a speed of 1/4 km per second. The runaway is 5 km. How many seconds does it take the plane

to get to the end of the runaway?
Engineering
1 answer:
Vikentia [17]3 years ago
8 0

Answer:

1 5segundos

Explanation:

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A flow of 12 m/s passes through a 6 m wide, 2 m deep rectangular channel with a bed slope of 0. 001. If the mean velocity of flo
prohojiy [21]

Answer:

manning's coefficient is 0.0357

Explanation:

Given:

Velocity of flow, v = 12 m/s

Width of the channel, b = 6 m

Depth of the channel, d = 2 m

bed slope, s = 0.001

mean velocity of flow, V = 1 m/s

now, the velocity is given as:

V= \frac{1}{n}R^{\frac{2}{3}}S^{\frac{1}{2}}

where,

n is the manning's coefficient

R is hydraulic mean depth

R = (Area of the channel) / (wetted Perimeter of the channel)

now,

R = (2 × 6) / ((2 × 2) + 6)

or

R = 12 / 10 = 1.2 m

now, on substituting the values in the equation for velocity, we get

1= \frac{1}{n}1.2^{\frac{2}{3}}(0.001)^{\frac{1}{2}}

or

n= 1.2^{\frac{2}{3}}(0.001)^{\frac{1}{2}}

or

n = 0.0357

hence, the value of manning's coefficient is 0.0357

8 0
3 years ago
Identify the measurement shown in figure 7 and state in centimeters ​
Sav [38]

Answer:

1.3cm

Explanation:

the arrow is 3 lines past the 1 so it is 1.3cm

6 0
3 years ago
A BOD test is to be run on a sample of wastewater that has a five-day BOD of 230 mg/L. If the initial DO of a mix of distilled w
Alexxandr [17]

Answer:

Distribution factor P = =38.33

V = 7.826 ml

Explanation:

given details:

BOD =230 mg/l

DO inital = 8.0mg/l

DO final = 2.0mg/l

we know

BOD = [DO inital -DO final] * distribution factor

230 = [8 - 2] D.F

Distribution factor P = \frac{230}{6}

Distribution factor P = =38.33

THE RANGE OF WASTE WATER VOLUME IN 300 ml bottle is

distribution factor = \frac{300}{V}

V = \frac{300}{38.33}

V = 7.826 ml

6 0
3 years ago
The electron beam in a TV picture tube carries 1015 electrons per second. As a design engineer, determine the voltage needed to
leonid [27]

Answer:

The voltage needed to accelerate the electron beam is 2.46 x 10^16 Volts

Explanation:

The rate of electron flow is given as:

q = 1015 electrons per second

The total current is given by:

Total Current = (Rate of electron flow)(Charge on one electron)

Total Current = I = (1015 electrons/s)(1.6 x 10^-19 C/electron)

I = 1.624 x 10^-16 A

Now, we know that electric power is given as:

Electric Power = Current x Voltage

P = IV

V = P/I

V = 4 W/1.624 X 10^-16 A

<u>V = 2.46 x 10^16 Volts</u>

6 0
3 years ago
A car has a steering wheel with a 15 inch diameter that takes 18 lbs of Effort force to move is
elena-14-01-66 [18.8K]

Answer: A first class lever in static equilibrium has a 50lb resistance force and 15lb effort force. The lever's effort force is located 4 ft from the fulcrum.

Explanation:

4 0
2 years ago
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