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3 years ago

What is a good topic sentence when writing about what happens to your body if you drink a Coke ?

1 answer:

8 0

Based on research by health writer Wade Meredith, it explains that a 330ml can of Coca Cola contains so much sugar, your body should vomit - but the phosphoric acid "cuts the flavor", helping you keep the liquid down.

After 40 minutes, your blood sugar has spiked, your pupils dilated, and your blood pressure has risen.

• Here's what to drink to be healthy

The body starts to produce more dopamine, a neurotransmitter that controls the brain's pleasure centres - "physically the same way heroin works, by the way".

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A pendulum consists of a weight tied by a string that is attached to the ceiling. The diagram models the motion of the pendulum

Mashutka [201]

Pendulum under goes energy conversions from potential to kinetic and back to potential.

A pendulum consists of a long string to which a bulb is attached. The string is fastened to a point from which it can oscillate freely when displaced through a small angle.

The pendulum is an example of a system in which energy conversion takes place. The energy is converted from potential to kinetic and back to potential. Since the image was not shown in the question, we can not locate the specific points where the energy conversions occur.

Learn more: brainly.com/question/14759840

6 0

3 years ago

A wave has a period of 2 seconds and a wavelength of 4 meters. Calculate its frequency and speed. Note: Recall that the frequenc

Angelina_Jolie [31]

Answer:

frequency = 0.5 Hz and speed = 2 m/s

Explanation:

Given that,

The period of a wave, T = 2 s

Wavelength, $\lambda=4\ m$

If f be the frequency. So,

f = 1/T

$f=\dfrac{1}{2}\\\\f=0.5\ Hz$

Speed of a wave is given by :

$v=f\lambda\\\\v=0.5\times 4\\\\v=2\ m/s$

So, the frequency of the wave is 0.5 Hz and speed is 2 m/s.

4 0

4 years ago

A lens of focal length 15.0 cm is held 10.0 cm from a page (the object ). Find the magnification .

nevsk [136]

Answer:

Magnification, m = 3

Explanation:

It is given that,

Focal length of the lens, f = 15 cm

Object distance, u = -10 cm

Lens formula :

$\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}$

v is image distance

$\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-10)}\\\\v=-30\ cm$

Magnification,

$m=\dfrac{v}{u}\\\\m=\dfrac{-30}{10}\\\\m=3$

So, the magnification of the lens is 3.

3 0

3 years ago

A small boat is moving at a velocity of 1.93 m/s when it is accelerated by a river current perpendicular to the initial directio

olasank [31]

Answer:

16.405m/s

Explanation:

Given, initial velocity = u = 1.93m/s, acceleration = a = 0.750m/s2, time = t = 19.3s, final velocity = v= ?

Using the first equation of linear motion,

v = u + at

v = 1.93 + 0.750 x 19.3

v = 1.93 + 14.475

v = 16.405m/s

7 0

3 years ago

Read 2 more answers

A horizontal 745 N merry-go-round of radius

Arturiano [62]

Answer:

The kinetic energy of the merry-goround after 3.62 s is 544J

Explanation:

Given :

Weight w = 745 N

Radius r = 1.45 m

Force = 56.3 N

To Find:

The kinetic energy of the merry-go round after 3.62 = ?

Solution:

Step 1: Finding the Mass of merry-go-round

$m = \frac{ weight}{g}$

$m = \frac{745}{9.81 }$

m = 76.02 kg

Step 2: Finding the Moment of Inertia of solid cylinder

Moment of Inertia of solid cylinder I = $0.5 \times m \times r^2$

Substituting the values

Moment of Inertia of solid cylinder I

=> $0.5 \times 76.02 \times (1.45)^2$

=> $0.5 \times 76.02\times 2.1025$

=> $79.91 kg.m^2$

Step 3: Finding the Torque applied T

Torque applied T = $F \times r$

Substituting the values

T = $56.3 \times 1.45$

T = 81.635 N.m

Step 4: Finding the Angular acceleration

Angular acceleration , $\alpha = \frac{Torque}{Inertia}$

Substituting the values,

$\alpha = \frac{81.635}{79.91}$

$\alpha = 1.021 rad/s^2$

Step 4: Finding the Final angular velocity

Final angular velocity , $\omega = \alpha \times t$

Substituting the values,

$\omega = 1.021 \times 3.62$

$\omega = 3.69 rad/s$

Now KE (100% rotational) after 3.62s is:

KE = $0.5 \times I \times \omega^2$

KE = $0.5 \times 79.91 \times 3.69^2$

KE = 544J

6 0

4 years ago