1. The man will be able to move the rock. See diagram.
Moment of Man's force : 400 N * 1.2 meter = 480 N-m
Rock's Weight = 50 Kg * 9.8 m/sec² = 490 Newtons
Moment of Rock's weight : 490 N * 0.80 meters = 392 N-m
<em><u> Moment of Man's Force is MORE : 480 N-m > 392 N-m</u></em><em><u> So man will be able to lift the rock.</u></em>2. Let is look at the diagram - second one.
Let us assume that the fulcrum (Pivot) is placed at X meters from the rock.
So moment of Girl's force about Pivot = 200 N * (2 - X) meters = 400 - 200 X
Moment of Rock's weight = 490 N * X = 490 X
As the Girl is able to lift the rock, 400 - 200 X > 490 X
Hence 400 > 200 X + 490 X
400 > 690 X
X < 400/690 = 0.58 meters
<u>
<em> If the Pivot is placed closer than 0.58 meters or 58 cm to the Rock, then </em></u>
<u>
<em> she can lift the rock.</em></u>
Answer:
40.3 m/s
Explanation:
We'll begin by calculating the resultant force.
Resultant force = 2000 – 1000 = 1000N
Next we shall determine the acceleration of the car. This is illustrated below:
Mass of the car = 2000kg
Resultant Force = 1000N
Acceleration =.?
Resultant Force = Mass x Acceleration
1000 = 2000 x Acceleration
Divide both side by 2000
Acceleration = 1000/2000
Acceleration = 0.5m/s²
Finally, we shall determine velocity of the car when it has moved 1000m.
Initial velocity (u) = 25m/s
Acceleration (a) = 0.5m/s²
Distance (s) = 1000m
Final velocity (v) =..?
Applying the formula v² = u² + 2as we can obtain the velocity of the car at 1000m as follow:
v² = u² + 2as
v² = 25² + 2(0.5 x 1000)
v² = 625 + 2(500)
v² = 625 + 1000
v² = 1625
Take the square root of both side
v = √1625
v = 40.3 m/s
Therefore, the speed of the car when it has moved 1000m is 40.3 m/s
Answer:
15 N to the right.
Explanation:
100 N to the right -->
85 N to the left <--
So therefore in order to find the net force of where the sled is being dragged towards is 100 N - 85 N = 15 N.
So the sled is moving towards the right of 15 N.
Answer:
hello your question has some missing parts below is the complete question
and the missing diagram
The two speakers emit sound that is 180° out of phase and of a single frequency,ƒ, Find the lowest two frequencies that produce a maximum sound intensity at the positions of Moe and Curly.
answer : 1316.2 hertz
Explanation:
The frequency that produce the maximum sound intensity can be calculated using the relation below
dsin ∅ = n <em>A</em>
where <em>A = </em>dsin ∅ / n when n = 1 . d = 0.800
<em>A</em> = 0.800 * ( 1 / 3.162 )
<em>A</em> = 0.253 m
speed of sound = 333 m/s
frequency = speed /<em> A</em>
<em>= </em>333 / 0.253 = 1316.2 hertz
this is how to convert BTU (IT) to Joules:
1 BTUIT = 1055.05585262 J
So the energy conversion from BTU to joules is given by the formula:
E(J) = 1055.05585262 ⋅ E(BTU)
BUT HERE IS THE ANSWER TO YOUR QUESTION
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