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8090 [49]
3 years ago
13

5. Which contains more nitrogen: 60g of urea, (NH2)2CO, or 100g of ammonium sulphate, (NH4)2SO4

Chemistry
1 answer:
topjm [15]3 years ago
5 0

Answer:

Urea contains more nitrogen

Explanation:

1 mole of Urea contains 2 moles of Nitrogen and 1 mole of ammonium sulfate contains, also, 2 moles of nitrogen.

60g of urea (Molar mass: 60g/mol) contains:

60g × (1mol / 60g) = 1 mole. As 1 mole of urea contains 2 moles of nitrogen, moles of nitrogen are 2.

100g of ammonium sulfate (Molar mass: 132g/mol) contains:

100g × (1mol / 132g) = 0.758 moles.

As 1 mole of urea contains 2 moles of nitrogen, moles of nitrogen are 0.758×2 = 1.516 moles.

That means, <em>urea contains more nitrogen</em>.

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Which of the following displays the correct change in enthalpy and best describes the reaction below? 2CsCl(aq) + Na2SO4(aq) 2Na
Bond [772]
We subtract the enthalpies of the reactants from that of the products:
2\Delta&#10; H(NaCl)+\Delta H(Cs_2 SO_4)-2\Delta H(CsCl)-\Delta H(Na_2 SO_4) \\ &#10;=2(-411)+(-1400) -2(-415)-(-1380) \\ = -12 kJ
Since this is < 0, this is an exothermic reaction.

3 0
3 years ago
What is the boiling point of a 1.5 m aqueous solution of fructose? the boiling point elevation constant of water is 0.515°c/m.
GREYUIT [131]
Answer is: <span>he boiling point of a 1.5 m aqueous solution of fructose is </span>100.7725°C.
The boiling point elevation is directly proportional to the molality of the solution according to the equation: ΔTb = Kb · b.<span>
ΔTb -  the boiling point elevation.
Kb - the ebullioscopic constant. of water.
b - molality of the solution.
Kb = 0.515</span>°C/m.
b = 1.5 m.
ΔTb = 0.515°C/m · 1.5 m.
ΔTb = 0.7725°C.
Tb(solution) = Tb(water) + ΔTb.
 Tb(solution) = 100°C + 0.7725°C = 100.7725°C.
5 0
3 years ago
A crow flies 100 meters east in 5 minutes. What is the crow’s velocity?​
torisob [31]

<em>Answer:</em>  20 m/min east

<em>Explanation:</em>  The speed is distance divided by time

distance between start-point and end-point = 100 meters

<em>time to cover the distan</em>ce  =  5 minutes

100 m ÷ 5 min = 20 m/min east

y<u>ou have to add east since velocity is the measure of speed and direction and your answer needs to include the direction</u>

3 0
2 years ago
An unknown amount of mercury (II) oxide was decomposed in the lab. Mercury metal was formed and 5.20 L of oxygen was released at
Yakvenalex [24]

Answer:

  • <u>68.3g</u>

Explanation:

<u>1. Word equation:</u>

  • <em>mercury(II) oxide → mercury + oxygen </em>

<u>2. Balanced molecular equation:</u>

  • 2HgO → 2Hg + O₂(g)

<u>3. Mole ratio</u>

Write the ratio of the coefficients of the substances that are object of the problem:

       2molHgO/1molO_2

<u>4. Calculate the number of moles of O₂(g)</u>

Use the equation for ideal gases:

          pV=nRT\\\\\\n=\dfrac{pV}{RT}\\\\\\n=\dfrac{0.970atm\times5.20L}{0.08206atm.L/K.mol\times 390.0K}\\\\\\n=0.1576mol

<u>5. Calculate the number of moles of HgO</u>

         \dfrac{2molHgO}{1molO_2}\times 0.1576molO_2=0.315molHgO

<u>6. Convert to mass</u>

  • mass = # moles × molar mass

  • molar mass of HgO: 216.591g/mol

  • mass = 0.315mol × 216.591g/mol = 68.3g

7 0
3 years ago
Dan got into his car in the middle of summer. When he sat on the hot black leather seats, he burned his legs. His sister said th
LekaFEV [45]

The correct answer is D) Dan's sister was correct because Dan's legs touched the car seats. That is an indicator of heat transfer by conduction.

Conduction only happens when a heated object touches a non-heated (or not as heated) object. Radiation did cause the car to become hot, but conduction caused Dan to get burned.

Hope this helps!! :D

3 0
3 years ago
Read 2 more answers
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