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3 years ago

5. Which contains more nitrogen: 60g of urea, (NH2)2CO, or 100g of ammonium sulphate, (NH4)2SO4

Chemistry

1 answer:

topjm [15]3 years ago

5 0

Answer:

Urea contains more nitrogen

Explanation:

1 mole of Urea contains 2 moles of Nitrogen and 1 mole of ammonium sulfate contains, also, 2 moles of nitrogen.

60g of urea (Molar mass: 60g/mol) contains:

60g × (1mol / 60g) = 1 mole. As 1 mole of urea contains 2 moles of nitrogen, moles of nitrogen are 2.

100g of ammonium sulfate (Molar mass: 132g/mol) contains:

100g × (1mol / 132g) = 0.758 moles.

As 1 mole of urea contains 2 moles of nitrogen, moles of nitrogen are 0.758×2 = 1.516 moles.

That means, <em>urea contains more nitrogen</em>.

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How many moles of HCl are present in 4.7 L of a 4.23 M HCl solution?

REY [17]

Hey There!

Volume = 4.7 L

Molarity = 4.23 M

Therefore:

n = M *V

n = 4.23 * 4.7

n = 19.881 moles of HCl

hope this helps!

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3 years ago

Magnesium reacts with a certain element to form a compound with the general formula MgX. What would the most likely formula be f

ziro4ka [17]

Answer:K2X

Explanation: Valency can be defined as the combining power of an element. It is the valency that dictates the value an element will have when writing a chemical formula for its compound.

MgX is a compound of magnesium and an element X. The valency of magnesium in most of its compound is +2. Now for the 2 to have been absent in the chemical formula, this shows that the element X itself have a valency if -2 for the valencies of both to have canceled out.

Now considering the element potassium, it is an alkaline metal belonging to group 1 of the periodic table. Hence, it is expected that it has a valency of +1

Forming a compound with element X means there would be an exchange of valencies between the two. We have established that x has a valency of -2. The formula of the compound thus formed by exchanging the valencies of both element would be K2X

7 0

2 years ago

Read 2 more answers

How many atoms are in 35.1 g of sodium chloride (NaCl) ?

hoa [83]

Answer:

I believe that there are 70.2

Explanation:

There are 2 atoms in sodium chloride so I x 35.1 by 2 and got 70.2

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3 years ago

To calculate the frequency of an electromagnetic wave, you need to know the speed of the wave which you already know as 186000 m

nirvana33 [79]

To finish calculating the frequency of an electromagnetic wave, you need the wavelength

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3 years ago

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A sample compound with a molar mass of 34.00g/mol is found to consist of 0.44g H and 6.92g O. Calculate both empirical and molec

balu736 [363]

Answer:

E.F= OH

M.F= $O_{2} H_{2}$

Explanation:

Empirical Formula

Step 1: Calculate mols of each element

0.44gH(1 mol H/ 1.008g H)= 0.4365 mol H

*note leave extra sig figs for calculations

6.92gO(1 mol O/ 16 g O)=0.4325 mol O

Step 2: Identify which is the smallest mol

*in this case 0.4365 mol H> 0.4325 mol O so we will use 0.4325 mol O

Step 3: Divide above calculations by the smallest mol

0.4325 mol O/0.4325= 1

0.4365 mol H/0.4325= 1.009 *rounds to 1

Step 4: use calculations as subscripts

Oxygen = 1 so the subscript will 1 (O)

Hydrogen = 1 so the subscript will 1 (H)

making E.F= OH

Molecular Formula:

Step 1: identify molecular mass and mass from the E.F

the molecular mass is given 34.00g/mol

the mass of the E.F is

(oxygen mass from periodic table)+(hydrogen mass from periodic table)

16+1.008= 17.008

Step 2:Divide the molecular mass by the mass given by the emipirical formula.

$\frac{34.00}{17.008}= 1.999$ round to 2

Step 3:Multiply the empirical formula (the subscripts) by this number to get the molecular formula. ANSWER: M.F=2(OH)- $O_{2} H_{2}$

3 0

3 years ago