The empirical formula CH₂ has a mass [(12 × 1) + (1 × 2)] = 14 g/mol
If the empirical formula is 14 g/mol,
and the molecular formula is ~140 g/mol
Then the multiple is = 140 g/mol ÷ 14 g/mol
= 10
Therefor the molecular formula is 10(CH₂) = <span>C</span>₁₀<span>H</span>₂₀<span> </span>
Answer:
Cl2(g) (green/yellow mix) + 2KBr(s) (white) ---> 2KCl(s) (violet) + Br2(g) (reddish brown)
This chemical reaction is a redox type.
Explanation:
Look at the oxidation state, when the number increase your element gets oxidated, when the number decrease, the elements it's getting reduced.
I uploaded the answer to
a file hosting. Here's link:
bit.ly/3gVQKw3
Answer:
We expect the enthalpies of combustion of two isomers to be different.
The molecular formular of the two molecules are very similar.
So the balanced chemical equation for the two combustion reactions are the same.
Explanation:
In calculation of the combustion enthalpiesfrom the isomers of the products and reactant.
The difference will be in the standard enthalpies of formation of the two combustion products.
The rod-shaped n- octane has vibrational and rotational motion possible more than the almost spherical neoprene.
Answer:
Yes it was
Explanation:
It was broken because they did not know what they were doing
